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3 years ago

Carlota does 2000 J of work on a machine. The machine does 500 J of work. What is the efficiency of the

Physics

2 answers:

jeyben [28]3 years ago

7 0

I am pretty sure it’s 75%

BARSIC [14]3 years ago

6 0

Answer:

25%

Explanation:

500 J out of 2000 J is 25%

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A typical human consumes 2500 Kcal of energy during a day. This is the equivalent to 10,450,000 J! Say you decided to run stairs

defon

Answer:

2940.1 joules would you burn in climbing stairs all day.

Explanation:

Work = W = F $\times$ d

going up stairs would be against force of gravity

W = mgh

where h is the height

the question is not complete because we need speed or distance

h = v $\times$ t

so assuming 1 step per second

h = 86,400 steps $\times$ 7inchs/step $\times$ 0.0254 m/inch

h = 15362 m

so from this

W = 800 N $\times$ 15362

= 12289600 J

that means YOU need 12289600 J to walk 1 step per second all day

divide that by 4180 J /Kcal

Kcal = $\frac{W}{(J/Kcal)}$

= $\frac{12289600}{4180}$

= 2940.1 Kcal

if you ran faster you would use more energy 2 steps per second would mean 5880 Kcal.

8 0

4 years ago

Select all of the answers that apply.

postnew [5]

Here are the answers to the given question above.
Relative dating uses laws or principles of stratigraphy and paleontology. These laws of relative dating are:
-law of original horizontality
-law of superposition
-law of original lateral continuity
-law of cross-cutting or intrusive relationships
Hope these are the answers that you are looking for.

3 0

3 years ago

Read 2 more answers

Pls reply... plss!! help me

viktelen [127]

Answer:

this is your solution

Explanation:

Answer-1 Iodine

Answer-2 Uterus

Answer-3 Adam's Apple

Answer-4 Distance

Answer-5 Carbon dioxide

Answer-6 Zygote

7 0

3 years ago

A railroad car moving at a speed of 3.46 m/s overtakes, collides and couples with two coupled railroad cars moving in the same d

I am Lyosha [343]

Answer:

$2.09\ \text{m/s}$

$22298.4\ \text{J}$

Explanation:

m = Mass of each the cars = $1.6\times 10^4\ \text{kg}$

$u_1$ = Initial velocity of first car = 3.46 m/s

$u_2$ = Initial velocity of the other two cars = 1.4 m/s

v = Velocity of combined mass

As the momentum is conserved in the system we have

$mu_1+2mu_2=3mv\\\Rightarrow v=\dfrac{u_1+2u_2}{3}\\\Rightarrow v=\dfrac{3.46+2\times 1.4}{3}\\\Rightarrow v=2.09\ \text{m/s}$

Speed of the three coupled cars after the collision is $2.09\ \text{m/s}$ .

As energy in the system is conserved we have

$K=\dfrac{1}{2}mu_1^2+\dfrac{1}{2}2mu_2^2-\dfrac{1}{2}3mv^2\\\Rightarrow K=\dfrac{1}{2}\times 1.6\times 10^4\times 3.46^2+\dfrac{1}{2}\times 2\times 1.6\times 10^4\times 1.4^2-\dfrac{1}{2}\times 3\times 1.6\times 10^4\times 2.09^2\\\Rightarrow K=22298.4\ \text{J}$

The kinetic energy lost during the collision is $22298.4\ \text{J}$ .

6 0

3 years ago

If cells were not able to obtain amino acids, what macromolecule would not be able to be synthesized

Zielflug [23.3K]

Answer:

protein

Explanation:

protein is a very large complex macro-molecule that requires amino acids

5 0

3 years ago