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tangare [24]
3 years ago
15

Tim puts his spare change in a jar each day when he comes home. When the jar is full he separates the coins and takes them to th

e bank. The coins would be classified as a _________. A) compound B) element C) mixture D) solution
Physics
1 answer:
xxTIMURxx [149]3 years ago
6 0

The bunch of stuff in the jar is a <em>mixture. </em> The different kinds of pieces aren't bound to each other, and they can be easily separated.

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a car slows down from 22 m/s to 3 m/s at a constant rate of 3.5 m/s squared. how many seconds are required before the car is tra
Stolb23 [73]

Answer:

9.05 s

Explanation

v=u+at

6 0
3 years ago
Calculate the number of moles of water molecules in 12 dm' of water<br>vapour at STP.<br><br>​
Vinvika [58]

Answer:

22.4 \:  {dm}^{3}  \: are \: occupied \: by \: 1 \: mole \\ 12 \:  {dm}^{3}  \: will \: be \: occupied \: by \: (  \frac{12}{22.4} ) \: moles \\  = 0.536 \: moles

4 0
3 years ago
a 150 kg object takes a 1.5 minute travel to a 2500 straight path it begins you trip at traveling 120 miles an hour and it decel
crimeas [40]
I believe it’s acceleration is -1.11 m/s^2
5 0
3 years ago
A 11,000-kg train car moving due east at 21.0 m/s collides with and couples to a 23,000-kg train car that is initially at rest.
Tomtit [17]

Answer:

v = 6.79 m/s

Explanation:

It is given that,

Mass of a train car, m₁ = 11000 kg

Speed of train car, u₁ = 21 m/s

Mass of other train car, m₂ = 23000 kg

Initially, the other train car is at rest, u₂ = 0

It is a case based on inelastic collision as both car couples each other after the collision. The law of conservation of momentum satisied here. So,

m_1u_1+m_2u_2=(m_1+m_2)V

V is the common velocity after the collisions

V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{11000\times 21}{(11000+23000)}\\\\V=6.79\ m/s

So, the two car train will move with a common velocity of 6.79 m/s.

6 0
3 years ago
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.5
Marat540 [252]

Answer:

Option C

Explanation:

From the question we are told that:

Mass m=0.015kg

Radius r=0.5m

Time t=0.70

Generally the equation for Tension is mathematically given by

 T=\frac{4mr}{t^2} \pi

 T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)

 T=0.60N

Therefore

T=0.60 N, toward the center of the circle

Option C

3 0
3 years ago
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