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nika2105 [10]
4 years ago
15

Mr. mole left his burrow that lies 7 meters below the ground and started digging his way deeper into the ground, descending at a

constant rate. After 6 minutes, he was 16 meters below the ground.
Let A(t)A(t)A, left parenthesis, t, right parenthesis denote Mr. Mole's altitude relative to the ground AAA (measured in meters) as a function of time ttt (measured in minutes).
What's the functions formula?
Mathematics
2 answers:
Dimas [21]4 years ago
7 0

Answer:

f(t)=-\frac{3}{2}t-7

Step-by-step explanation:

We know that:

  • The initial conditions are -7 meters at 0 minutes.
  • Then, after 6 minutes, he was 16 meters below the ground.

According to these two simple facts we can found the linear function that describes this problem. First, the problem says that Mr. Mole is descending at a constant rate, which is the slope of the function. Now, to calculate the slope we need to points, which are (0;-7) and (6;-16), where <em>t-values </em>are minutes, and <em>y-values </em>are meters. You can see, that the first point is the initial condition and the second point is 6 minutes later.

So, we calculate the slope:

m=\frac{y_{2}-y_{1}}{t_{2}-t_{1}} \\m=\frac{-16-(-7)}{6-0}=\frac{-16+7}{6}=\frac{-9}{6}=\frac{-3}{2}

From the slope we can see that Mr. Mole is descending, because it has a negative sign. Also, the point (0;-7) is on the <em>y-axis</em>, because <em>t</em> is null, so -7 is part of the function. Therefore the function that describes this problem is:

f(t)=-\frac{3}{2}t-7

Juliette [100K]4 years ago
7 0

Answer:

A(t)=-1.5t-7

Step-by-step explanation:

It is given that Mr. Mole left his burrow that lies 7 meters below the ground and after 6 minutes, he was 16 meters below the ground.

It means the line passing thought the points (0,-7) and (6,-16). It means the initial value is -7.

He started digging his way deeper into the ground, descending at a constant rate. The rate of change is

The rate of change is -1.5.

A(t) denote Mr. Mole's altitude relative to the ground A (measured in meters) as a function of time t (measured in minutes).

Therefore the function's formula is , here negative sign shows the Mr. Mole's altitude relative to below the ground A

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The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha
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Answer:

a)P(X>66)=P(Z>1)=1-P(Z

b)P(\bar X >66)=P(Z>2)=1-P(Z

c) P(\bar X >66)=P(Z>10)=1-P(Z

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(64,2)  

Where \mu=64 and \sigma=2

We are interested on this probability

P(X>66)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-\mu}{\sigma})=P(Z>\frac{66-64}{2})=P(Z>1)

And we can find this probability on this way:

P(Z>1)=1-P(Z

3) Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{4}}}=2)

And using a calculator, excel or the normal standard table we have that:

P(Z>2)=1-P(Z

4) Part c

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{100}}}=10)

And using a calculator, excel or the normal standard table we have that:

P(Z>10)=1-P(Z

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