Based on the ratios of the peanuts mixed with raisins in the versions of the trail mix, the ratios are equivalent for both mixes.
<h3>What are the ratios?</h3>
The first ratio is:
3 : 2
When taken to the simplest terms it is:
3/2 : 2/2
1.5 : 1
The second ratio is:
4.5 : 3
4.5/3 : 3/3
1.5 : 1
The ratios of the peanut and raisins mix are therefore equivalent.
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Answer:
Step-by-step explanation:
Given.
Two points are given.
and 
An exponential function is in the general form.
-------(1)
We know the points 
and 
put the first point value in equation 1
--------(2)
put the second point value in equation 1
----------(3)
Put the a value from equation 2 to equation 3
![b^{4} = 16\\b=\sqrt[4]{16} \\b=2](https://tex.z-dn.net/?f=b%5E%7B4%7D%20%3D%2016%5C%5Cb%3D%5Csqrt%5B4%5D%7B16%7D%20%5C%5Cb%3D2)
Put the b value in equation 2
Put the a and b value in equation 1
So, the exponential function that passes through the points and 
are .
A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
