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Airida [17]
3 years ago
9

What the expression m/5 represent?

Mathematics
1 answer:
katrin [286]3 years ago
7 0
A variable (m) divided by a number (5)

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In the diagram, ΔPMN ≅ ΔQSR.
kotykmax [81]
20. qr is congruent to pn so pn is 20
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3 years ago
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Find the sum of the measures of Angle A, Angle B, Angle C and Angle D.
12345 [234]

Answer:

Q:

my problem is this. Solve the problem.The sum of the measures of the angles in any triangle is 180 degrees. In triangle ABC, angles A and B have the same measure, while angle C is 42 degrees larger t…

A:

In triangle ABC, angles A and B have the same measure, while angle C is 42 degrees larger than each of the other two angles. Find the measure of angle Step-by-step explanation:

Find the measures of angles A, B, and C in triangle ABC, if measure of angle B = 5 times the measure of angle A measure of angle C = measure of angle A + 110

✓ A + B + C = 180 A + 5A + A+110 = 180

4 0
3 years ago
A triangle with an area of 23 cm² is dilated by a factor of 6.
Jlenok [28]
For this item, I will assume that we are required to give the area of the dilated triangle. By dilated we mean to say that the dimensions of the second triangle is 6 times that of the first. We square 6 and them multiply this to the area of the original triangle to get the area of the second. That is,
                     area of second triangle = (2/3 cm²)(6²) = 24 cm²
Thus, the area of the new triangle is equal to 24 cm².
8 0
4 years ago
I don't understand this, please help ​
dimulka [17.4K]

Answer:

∠2 = 150°, it is a supplementary angle to 30°

∠3 = 30°, it is an alternate angle to 30°

∠4 = 150°, it is a supplementary angle to 30°

∠5 = 30°, it is an alternate angle to 30°

∠6 = 150°, it is a supplementary angle to 30°

∠7 = 30°, it is an alternate angle to 30°

∠8 = 150°, it is a supplementary angle to 30°

6 0
3 years ago
a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o
NemiM [27]

Answer:

Average = -1°C

Step-by-step explanation:

The data recorded is;

6, -7, -5, 5, -8, 3 (in °C)

Average = \frac{6 - 7 - 5 + 5 - 8 + 3}{6} = -1°C

8 0
3 years ago
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