Answer:
348 + 395 = 743
Hence, together they have 743 pennies and not 653 pennies. And we cannot perform the rounding, as that is the case when we have the decimal number or the float number. Only then we have the digits after the decimal. And if it's more than 5, we add 1 to the previous or else leave the number as it is. And we go on performing from right to left, and till the number of decimal places, we need to round off. However, here its purely an integer, and hence we cannot round off, as that will result in a significant loss, and which is not acceptable. However, if we want to round off before decimal places as well, then in that case 743 will be $7s, and 653 pennies will be 6+1= $7s, and if this level of loss is acceptable then we can assume that they have the same sum of money. However, here the answer is given in pennies, and hence this is not the case. And hence the answer given in the question is not correct.
Explanation:
The answer is self-explanatory. And since both are numbers, rounding is not required(as explained in the answer section), as it is required in case of decimal and float(as explained in the answer section). And as explained in the answer section, if we can tolerate very heavy loss, then the numbers as well can be rounded off as explained in the answer section. But that is not the case here, as the answer is given in pennies.
Answer:
4. let eggs = 5
let bread = 10
let soda = 6
5.
let total = eggs+bread+soda
Answer:
Check the explanation
Explanation:
Kindly check the attached images below to the see the step by step explanation to the question above.
Answer:
The first argument listed after IF
Explanation:
When the two variables are listed next to each other, Excel will find and calculate the correlation between them.
Answer:
Explanation:
A general idea is that you should repeat the simulation until the results converge. An easy but illustrative example of this is that we want to see if the R function rbinom is accurate in simulating a coin toss with a given probability. We will simulate one coin toss 10000 times, and plot the percentage of heads against the number of coin tosses:
set.seed(1)
n <- 10000
result <- NULL
percent <- NULL
for (i in 1:n) {
result[i] <- rbinom(1,1,0.5)
percent[i] <- sum(result)/i
}
plot(seq(1:10000),percent, type="l")
abline(0.5, 0, lty=2)
