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jekas [21]
4 years ago
15

An auto, starting from rest, undergoes constant acceleration and covers a distance of 1200 meters. The final speed of the auto i

s 60 meters/sec. How long does it take the car to cover the 1200 meters?
Physics
1 answer:
Elanso [62]4 years ago
8 0

Answer:

It will take 40 sec

Explanation:

We have given that auto is starting from rest so initial velocity u = 0 m/sec

And final velocity is given as v = 60 m/sec

Distance traveled by car s = 1200 m

According third equation of motion we know that v^2=u^2+2as

So 60^2=0^2+2\times a\times 1200

a=1.5m/sec^2

Now according to first equation of motion v = u+at

So 60=0+1.5\times t

t = 40 sec

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Jaipal measures a circuit at 1.2 A and 24 . Using Ohm’s law, what can he calculate for the circuit? current (C) current (I) volt
jenyasd209 [6]

Answer: voltage (V)

Explanation:

Hi, in the answer the letter A (1.2 A) stands for Ampere, and the symbol next to the number 24 must be Ω 8 (Ohms)

So, applying Ohm's law:

Voltage (V) =current (I) x resistance (R)

V = I x R

Replacing with the values given;

V = 1.2 A x 24Ω

In conclusion, we can calculate the value of Voltage for the circuit.

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
Read 2 more answers
A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th
Nesterboy [21]

Answer:

Option C is the correct answer.

Explanation:

By Charles's law we have

        V ∝ T

That is

       \frac{V_1}{T_1}=\frac{V_2}{T_2}

Here given that

      V₁ = 0.20 cubic meter

      T₁ = 333 K

      T₂ = 533 K

Substituting

      \frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{0.20}{333}=\frac{V_2}{533}\\\\V_2=\frac{0.20}{333}\times 533=0.3198m^3

New volume of the gas  = 0.3198 m³

Option C is the correct answer.

7 0
4 years ago
The quantum model suggests that electrons __________.
yan [13]

The correct answer is (d), electrons are in probable cloud location.

An atom is made up of three fundamental particles, electron, proton and neutron. Proton and neutron are located in the nucleus, while the electrons orbit the nucleus in relative large orbit, however the exact position of the electron in the shall is highly unpredictable, therefore they are assumed to be in probable cloud location where the probability of finding an electron is very high.

3 0
4 years ago
An automobile has a vertical antenna 1.45 m long. The automobile travels at 90 km/h on a horizontal road where the Earth's magne
aivan3 [116]

Answer:

9.05\times 10^{-4} V

Explanation:

We are given that

Length of antenna,l=1.45 m

Earth's magnetic field,B=59\mu T=59\times 10^{-6} T

1\mu=10^{-6}

\theta=65.5^{\circ}

Speed,v=90 km/h=90\times \frac{5}{18}=25m/s

1km/h=\frac{5}{18}m/s

Magnitude of maximum induced emf in the antenna=E=Blvcos\theta

Substitute the values

E=59\times 10^{-6}\times 1.45\times 25cos65

E=9.05\times 10^{-4} V

5 0
4 years ago
All scientists try to base their conclusions on _____.
Elodia [21]
The information they already have, what they know and what they see
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