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jekas [21]
4 years ago
15

An auto, starting from rest, undergoes constant acceleration and covers a distance of 1200 meters. The final speed of the auto i

s 60 meters/sec. How long does it take the car to cover the 1200 meters?
Physics
1 answer:
Elanso [62]4 years ago
8 0

Answer:

It will take 40 sec

Explanation:

We have given that auto is starting from rest so initial velocity u = 0 m/sec

And final velocity is given as v = 60 m/sec

Distance traveled by car s = 1200 m

According third equation of motion we know that v^2=u^2+2as

So 60^2=0^2+2\times a\times 1200

a=1.5m/sec^2

Now according to first equation of motion v = u+at

So 60=0+1.5\times t

t = 40 sec

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Answer:

a) 10.29° upstream

b) t=338.7s

Explanation:

If the river is 1km wide and the destination point is 0.5km away downstream, then the angle and distance the the boat has to travel is:

\alpha =atan(\frac{0.5}{1})=26.56°

D=\sqrt{1^2+0.5^2}=1.118km

The realitve velocity of the boat respect to the water is:

V_{B/W}=[3*cos\beta ,3*sin\beta ]  where β is the angle it has to be pointed at.

From the relative mvement equations:

V_{B/W}=V_B-V_W  where V_B=[V*cos\alpha ,-V*sin\alpha ]

From this equation we get one equation per the x-axis and another for the y-axis. If we square each of them and add them together, we will get 2 equations:

(3*cos\beta )^2+(3*sin\beta )^2=(V*cos\alpha )^2+(-V*sin\alpha +2)^2

V^2-4*V*sin\alpha -5=0  Solving for V:

V = 3.3m/s   and   V=-1.514m/s   Replacing this value into one of our previous x or y-axis equations:

\beta =acos(\frac{V*cos\alpha }{3} ) = 10.29°

The amount of time:

t = D/V = \frac{1118m}{3.3m/s} =338.7s

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This is defined as a propagation of disturbances from place to place in a regular and organized way.

The answers provided above are therefore the most appropriate choices in this scenario.

Read more about Waves here brainly.com/question/15663649

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