Answer:
F = 2.30 10⁴ N
Explanation:
The force required to link two gates must be equal to or greater than the electrostatic force of repulsion, because the protons have equal charges.
F = k q₁ q₂ / r²
Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C²
In this case the proton charge is 1.6 10⁻¹⁹ C and the distance between them is approximately the diameter of the core r = 10⁻¹⁵ m
Let's calculate
F = 8.99 10⁹ (1.6 10⁻¹⁹)² / (10⁻¹⁵)²
F = 2.30 10⁴ N
The bond strength must be equal to or greater than this value
Answer:
hence the y - component of the velocity is 50m/s
Answer: 1666J
Explanation:
Given that,
Mass of box (m) = 10kg
Total distance covered by box (h)
= (5m + 12m)
= 17m
work done on the box = ?
Work is done when force is applied on an object over a distance. Hence, the magnitude of work done on the box depends on its mass (m), distance covered (h), and acceleration due to gravity (g)
(g has a value of 9.8m/s²
i.e Work = mgh
Work = 10kg x 9.8m/s² x 17m
Work = 1666J
Thus, 1666 joules of work was done by the woman on the box.
