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3 years ago

When a potassium atom forms an ion, it loses one electron. What is the electrical charge of the potassium ion?

2 answers:

3 0

If a potassium atom loses one electron than it becomes a +1 charge, because the electrons are negative and the nucleus is positive (the positive comes from the protons). The protons and electrons balance out so it has a neutral charge, but if the atom loses an electrons it has a positive charge, but if the atom gains an electron than it becomes negative. the charge (+/- and the number) of the atom depends on how many electron the atom gains/loses.
the answer is (D.) +1

I hope this helps.

Ratling [72]3 years ago

3 0

Answer:

it is D

Explanation:

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A car moves 50km in the first 30 minutes and 50km in the second 30 minutes and continues in this way which motion is this ------

egoroff_w [7]

Answer:

Uniform rectilinear movement (m. r. u.)

Explanation:

It is a continuous movement without acceleration, that is, it moves at a constant speed. The speed does not change over time, for this reason, there is no change in acceleration.

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3 years ago

A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an

anyanavicka [17]

Answer:

The value of tangential acceleration $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

The value of radial acceleration $\alpha_{r} = 80 \frac{m}{s^{2} }$

Explanation:

Angular acceleration = 50 $\frac{rad}{s^{2} }$

Radius of the disk = 0.8 m

Angular velocity = 10 $\frac{rad}{s}$

We know that tangential acceleration is given by the formula $\alpha_{t} =$ $r \alpha$

Where r = radius of the disk

$\alpha$ = angular acceleration

⇒ $\alpha_{t} =$ 0.8 × 50

⇒ $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

This is the value of tangential acceleration.

Radial acceleration is given by

$\alpha_{r} = \frac{V^{2} }{r}$

Where V = velocity of the disk = r $\omega$

⇒ V = 0.8 × 10

⇒ V = 8 $\frac{m}{s}$

Radial acceleration

$\alpha_{r} = \frac{8^{2} }{0.8}$

$\alpha_{r} = 80 \frac{m}{s^{2} }$

This is the value of radial acceleration.

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3 years ago

Two large non-conducting plates of surface area A = 0.25 m 2 carry equal but opposite charges What is the energy density of the

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Answer:

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Explanation:

Using E = q/A*eo

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eo = 8.85*10^-12

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= [(75*10^-6)^2] / [2*(0.25)^2*8.85*10^-12]

= 5.1*10^3 J/m^3

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