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trasher [3.6K]
3 years ago
9

HELPPPP WILL MARK B IF CORRECT!!!!

Physics
2 answers:
sasho [114]3 years ago
7 0

Answer:

75 percent

Explanation:

mostly everyone has freckles

Vilka [71]3 years ago
6 0
If freckles is the dominant trait, this means every one of the genes with an upper case have freckles. This gives us:

3/4 of the offspring will have freckles. You can also say 75%

Hope this helps!! :)
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a dog walks 14 meters to the east and than 20 meters back to the west for the motion what is the distance moved
Mariana [72]
The dog moved 6 meters west and 34 meters total
8 0
3 years ago
Read 2 more answers
Given that a pipe having a diameter of 1.5 feet and a height of 10 feet, what is the psi at 5 feet ?
grin007 [14]

Answer:

The pressure is 2.167 psi.

Explanation:

Given that,

Diameter = 1.5 feet

Height = 10 feet

We need to calculate the psi at 5 feet

Using formula of pressure at a depth in a fluid

Suppose the fluid is water.

Then, the pressure is

P=\rho g h

Where, P = pressure

\rho = density

h = height

Put the value into the formula

P=1000\times9.8\times1.524

P=14935.2\ N/m^2

Pressure in psi is

P=2.166167621\ psi

P=2.167\ psi

Hence, The pressure is 2.167 psi.  

4 0
3 years ago
A flowerpot falls from a window sill 36.5 m
hram777 [196]

When a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

From Newton's third equation of motion,

v^2 = u^2 + 2gh

where,

h is the height of the object or body from ground

u is the initial velocity of the body or object

v is the final velocity of the body or object

g is the acceleration due to gravity

Now, as we know that

Flowerpot is at rest. So, u = 0

g = 9.81m/s^2

h = 36.5m

By substituting all the values, we get

v^2 = 2 × 9.81 × 36.5

= 716.13

v = 26.7m/s

Thus, we concluded that when a flowerpot falls from a window sill 36.5 m

above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.

learn more about Newton's equation of law of motion:

brainly.com/question/8898885

#SPJ9

7 0
1 year ago
The half-lives for the radioactive decay of various elements are listed below.
myrzilka [38]

Answer:

D ko alam pasensya ka na ha

4 0
3 years ago
Pulsars are neutron stars that emit X rays and other radiation in such a way that we on Earth receive pulses of radiation from t
stira [4]

Answer:

(a) a_{c} = 5.41\times 10^{9} m/s^{2}

(b) a_{t} = 2.99\times 10^{- 5} m/s^{2}

Given:

Time period of Pulsar, T_{P} = 33.085 ms == 33.085\times 10^{- 3} s

Equatorial radius, R = 15 Km = 15000 m

Spinning time, t_{s} = 9.50\times 10^{10}

Solution:

(a) To calculate the value of the centripetal  acceleration, a_{c} on the surface of the equator, the force acting is given by the centripetal force:

m\times a_{c} = \frac{mv_{c}^{2}}{R}

a_{c} = \frac{v_{c}^{2}}{R}                (1)

where

v_{c} = \frac{distance covered(i.e., circumference)}{ T}

v_{c} = \frac{2\pi R}{Time period, T}           (2)

Now, from (1) and (2):

a_{c} = R\frac({2\pi )^{2}}{T^{2}}

a_{c} = 15000\frac{2\pi )^{2}}{(33.085\times 10^{- 3})^{2}}

a_{c} = 5.41\times 10^{9} m/s^{2}

(b) To calculate the tangential acceleration of the object :

The tangential acceleration of the object  will remain constant and is given by the equation of motion as:

v = u + a_{t}t_{s} = 0

where

u = v_{c}

a_{t} = - \frac{2\pi R}{Tt_{s}}

a_{t} = - \frac{2\pi 15000}{33.085\times 10^{- 3}\times 9.50\times 10^{10}}

a_{t} = 2.99\times 10^{- 5} m/s^{2}

7 0
3 years ago
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