The answer to the set of questions are as follows:
a. 2 ( 2/w2C) = 4xc2 = Xl2 / Xc2 = 4
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The inductors reactance is greater than the capacitor
b. </span>(1/ 3w1C ) = (1/ 9w3C ) = 1/9 Xc3 = X l2/ Xc2 = 1/9
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The capacitors reactance is greater than inductor
I hope my answer has come to your help. God bless and have a nice day ahead!
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Answer: 109.89 Nm
Explanation:
The maximum torque will be calculated as the force multiplied by the perpendicular distance. This will be:
Torque = force × perpendicular distance
torque = 333 × 0.33
= 109.89 Nm
Given:
V1 = 4m3
T1 = 290k
P1 = 475 kpa = 475000 Pa
V2 = 6.5m3
T2 = 277K
Required:
P
Solution:
n = PV/RT
n = (475000 Pa)(4m3) / (8.314 Pa-m3/mol-K)(290k)
n = 788 moles
P = nRT/V
P = (788 moles)(8.314
Pa-m3/mol-K)(277K)/(6.5m3)
P = 279,204 Pa or 279 kPa
