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g100num [7]
3 years ago
12

Two large conducting parallel plates A and B are separated by 2.4 m. A uniform field of 1500 V/m, in the positive x-direction, i

s produced by charges on the plates. The center plane at x = 0.00 m is an equipotential surface on which V = 0. An electron is projected from x = 0.0 m. with an initial kinetic energy K = 300 eV, in the positive x-direction.
a. Determine the initial velocity of the electron at x = 0.0 m.
b. What is the potential difference between the plates?
c. At a certain point the electron stops momentarily and then reverses direction. What is the electric potential at this point?
d. What is the kinetic energy of the electron when it reaches plate A?
Physics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

a. 1.027 x 10^7 m/s b. 3600 V c. 0 V and d. 1.08 MeV

Explanation:

a. KE =1/2 (MV^2) where the M is mass of electron

b. E = V/d

c. V= 0 V (momentarily the pd changes to zero)

d KE= 300*3600 v = 1.08 MeV

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Find the current passing through each of the 3 resistors connected parallel to each other as shown in the figure (i1, i2, I3). S
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Answer:

I1 = ε/R1

I2 = ε/R2

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Explanation:

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Now, formula for current is; I = V/R

In this case, V which is voltage is denoted by ε.

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3 years ago
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kin
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Answer:

a = 0.1 m/s²

Explanation:

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  • Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:

       F_{net}  = F_{app} -F_{frk}  = 100 N - 70 N = 30 N (1)

  • By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:

       F_{net} = m* a = 300 Kg * a = 30 N (2)

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3 years ago
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0.41

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