Answer:
a) 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b) 3.466 × 10¹¹ N/C
Explanation:
a)
p(r) = -A exp ( - 2r/a₀)
Q = ₀∫^∞ ₀∫^π ₀∫^2xπ p(r)dV = -A ₀∫^∞ ₀∫^π ₀∫^2π exp ( - 2r/a₀)r² sinθdrdθd∅
Q = -4πA ₀∫^∞ exp ( - 2r/a₀)r²dr = -e
now using integration by parts;
A = e / πa₀³
p(r) = - (e / πa₀³) exp (-2r/a₀)
Now Net charge inside a sphere of radius a₀ i.e Qnet is;
= e - (e / πa₀³) ₀∫^a₀ ₀∫^π ₀∫^2π r² exp (-2r/a₀)dr
= e - e + 5e exp (-2) = 1.082 × 10⁻¹⁹C ( e = 1.6 × 10⁻¹⁹C)
b)
Using Gauss's law,
E × 4πa₀ ² = Qnet / ∈₀
E = 4πa₀ ² × Qnet × 1/a₀²
E = 3.466 × 10¹¹ N/C
Answer:
-6 m/s^2
Explanation:
30 - 90 = -60
-60 / 10 = -6
If acceleration was constant, it will be -6 m/s^2
<h2>
It takes 6.78 seconds to complete 12 dribbles.</h2>
Explanation:
Frequency of dribble = 1.77 Hz
That is
Number of dribbles in 1 second = 1.77

Now we need to find how long does it take for you to complete 12 dribbles.
Time taken for 12 dribbles = 12 x Time taken for 1 dribble
Time taken for 12 dribbles = 12 x 0.565
Time taken for 12 dribbles = 6.78 seconds
It takes 6.78 seconds to complete 12 dribbles.
I think that would be c) mirror because mirrors reflects light and can't create it.
The pressure exerted on the table due to the book is 200 N/m².
The given parameters;
- <em>mass of the book, m = 400 g = 0.4 kg</em>
- <em>dimension of the table, = 0.10m x 0.20 m.</em>
- <em>gravitational field strength g = 10 N/kg.</em>
The area of the table is calculated as follows;
A = 0.1 x 0.2 = 0.02 m²
The pressure exerted on the table due to the book is calculated as follows;

where;
- <em>F is the force of the book due to its weight</em>
<em />

Thus, the pressure exerted on the table due to the book is 200 N/m².
Learn more here:brainly.com/question/21935783