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Katyanochek1 [597]
3 years ago
13

How many sucrose molecules are in 3.0 moles of sucrose scientific

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0
Answer:
             1.80 × 10²⁴ Molecules of Sucrose

Solution:

Number of Moles and Number of Particles (molecules in given case) are related to each other as,

                  Moles  =  Number of Molecules ÷ 6.022 × 10²³

Solving for Number of Molecules,

                  Number of Molecules  =  Moles × 6.022 × 10²³

Data Given;
                     Moles  =  3 moles

Putting values in eq,


                 Number of Molecules  =  3 mol × 6.022 × 10²³


                 Number of Molecules  =  1.80 × 10²⁴ Molecules
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Answer:

3. The mass of ethanol required is approximately 0.522869 g

The mass of ethanoic acid required is approximately 0.68156 g

4. The mass of iron (III) oxide required is approximately 285.952.189.095 tonnes

5. The mass of silver nitrate required is approximately 14.53 grams

6. The mass of copper oxide that would be needed is approximately 31.86 grams

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c. The mass of the precipitate, Mg(OH)₂, formed is approximately 14.579925 grams

Explanation:

3. The 1 mole of ethanol and 1 mole of ethanoic acid combines to form 1 mole of ethyl ethanoate

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The number of moles of ethanoic acid = 1/88.11 moles

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The mass of ethanoic acid in the reaction = 60.052 g/mol × 1/88.11 moles ≈ 0.68156 g

4. 1 mole of iron(III) oxide reacts with 1 mole of CO₂ to produce 1 mole of iron

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6. The number of moles of CuSO₄·5H₂O in 100 g of CuSO₄·5H₂O = 100 g/(249.69 g/mol) ≈ 0.4005 moles

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2 moles of NaOH produces 1 mole of Zn(OH)₂

0.5 moles of NaOH will produce 0.5 mole of Zn(OH)₂

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b. 6 moles of NaOH produces 2 moles Al(OH)₃

20 g, or 0.5 mole of NaOH will produce (1/6) mole of Al(OH)₃

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The mass of the precipitate, Mg(OH)₂, formed, m = 58.3197 g/mol × (1/4) moles = 14.579925 grams

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