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Katyanochek1 [597]
3 years ago
13

How many sucrose molecules are in 3.0 moles of sucrose scientific

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0
Answer:
             1.80 × 10²⁴ Molecules of Sucrose

Solution:

Number of Moles and Number of Particles (molecules in given case) are related to each other as,

                  Moles  =  Number of Molecules ÷ 6.022 × 10²³

Solving for Number of Molecules,

                  Number of Molecules  =  Moles × 6.022 × 10²³

Data Given;
                     Moles  =  3 moles

Putting values in eq,


                 Number of Molecules  =  3 mol × 6.022 × 10²³


                 Number of Molecules  =  1.80 × 10²⁴ Molecules
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8. A wave has a frequency of 46 Hz and a wavelength of 2.1 meters. What is the speed of the wave?
AleksAgata [21]

Answer:

the speed of the wave is 96.6

Explanation:

to find do frequency x wavelength

6 0
3 years ago
I PLEASE HELP! How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 gr
PtichkaEL [24]
Moles of calcium metal used = 100/40.1=2.5
Moles of HBr need to react = 5 moles 
As the molar ratio is 1 is to 2 among them 
so
Moles=molarity x volume
5=2.25 x volume
volume=2.22 litres of HBr required for this reaction
ANSWER IS 2.22 LITRES
8 0
3 years ago
A gas with a pressure of 2.25 atm occupies 450.0 mL at a temperature of 300 K. What is the volume at 405.0 K?
Aneli [31]

The volume of the gas at a temperature of 405.0 K would be 607.5 mL. Making option D the right answer to the question.

What is the volume of the gas?

To find the volume of the gas, the equation to be used would have to be combine gas law.

Combine gas law as the name suggest uses the combination of Charles law which measures Volume against temperature, and Gay-Lussac's law which measures Pressure/Temperature, and Boyle's law  which measures pressure X volume where k is constant.

Using the combine law to find the volume, we have:

P₁V₁/T₁=P₂V₂/T₂

Where P₁ = initial pressure

           V₁ = initial volume

             T₁ = initial temperature

            P₂ = final  pressure

            V₂ = final  volume

            T₂ = final  temperature

P₁ = 2.25atm

V₁ = 450.0 mL

T₁ = 300 K

T₂ = 405.0 K

V₂ = ?

D) 607.5 mL

= [2.25(450)]÷300=[2.25(V₂]÷405

Making  V₂ the subject

 3.375=2.25 V₂ ÷ 405

V₂ = 3.375 x 405 ÷ 2.25

V₂ = 607.5 mL

In summary, a gas with an initial pressure of 2.25atm, an initial pressure of 450.0 mL and an initial temperature of 300 K would have a final volume of 607.5 mL if the temperature is increased to  405.0 K.

Learn more about Combine gas law here: brainly.com/question/13538773

#SPJ1

6 0
1 year ago
Evaluate ( a=2 b=3)...3a - 2b =​
skad [1K]

Hey!

---------------------------------------------------

Steps To Solve:

~Substitute

3(2) - 2(3)

~Subtract

6 - 6

~Simplify

0

---------------------------------------------------

Answer:

\Large\boxed{\mathsf{0}}

---------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
Read 2 more answers
What fraction of the carbon dioxide exhaled by animals is generated by the reactions of the citric acid cycle
puteri [66]

Answer:

1/3

Explanation:

Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.  

Pyruvate is converted to acetyl-CoA in the reaction given below:

Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂

1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.

Also,  

2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).

Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)

Thus,

<u>Fraction = 2/6 = 1/3</u>

4 0
3 years ago
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