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Katyanochek1 [597]
3 years ago
13

How many sucrose molecules are in 3.0 moles of sucrose scientific

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0
Answer:
             1.80 × 10²⁴ Molecules of Sucrose

Solution:

Number of Moles and Number of Particles (molecules in given case) are related to each other as,

                  Moles  =  Number of Molecules ÷ 6.022 × 10²³

Solving for Number of Molecules,

                  Number of Molecules  =  Moles × 6.022 × 10²³

Data Given;
                     Moles  =  3 moles

Putting values in eq,


                 Number of Molecules  =  3 mol × 6.022 × 10²³


                 Number of Molecules  =  1.80 × 10²⁴ Molecules
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Naddika [18.5K]
<h3><u>Answer;</u></h3>

A gas in a liquid

<h3><u>Explanation;</u></h3>
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3 years ago
If the solubility of a gas in water at 25°C is 22.25 mg/L at 2.5 atm of pressure, what is its solubility (in mg/L) at 25°C
tamaranim1 [39]

Answer:

8.9 mg/l

Explanation: Temp doesnt matter so throw that out automatically then your equation is;

S1/P1=S2/P2

We are looking for S2 and that equation is;

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A little bit of simple math and you get your answer: 8.9 mg/l

8 0
2 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

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V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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Tamiku [17]

Answer:

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Explanation:

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A molecule is a group of two or more atoms. They can be the same atom (homonuclear), such as or different atoms (heteronuclear).

Some examples of homonuclear molecules include:

Hydrogen  (H2)  

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Phosphorus  (P4)  

Some examples of heteronuclear molecules include:

Carbon dioxide  (CO2)  

Sulfuric acid  (H2SO4)  

Methane  (CH4)

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2 years ago
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Answer:

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