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kirill115 [55]
3 years ago
6

Compose one to two typewritten paragraphs summarizing the content of your poster. a) Explain in detail what happens as thermal e

nergy is added to the sealed containers. i. How does an increase in thermal energy affect the kinetic energy of the particles in each state of matter? ii. How does an increase in thermal energy affect the particle motion in each state of matter? iii. How does an increase in thermal energy affect the temperature of each state of matter? iv. How does an increase in thermal energy affect the state of matter? b) Explain in detail what happens as thermal energy is removed from the sealed containers. i. How does a decrease in thermal energy affect the kinetic energy of the particles in each state of matter? ii. How does a decrease in thermal energy affect the particle motion in each state of matter? iii. How does a decrease in thermal energy affect the temperature of each state of matter? iv. How does a decrease in thermal energy affect the state of matter?
Chemistry
1 answer:
vladimir2022 [97]3 years ago
8 0

sad. no one answered this

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The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces
Oxana [17]

Answer:

1. NaN₃(s) → Na(s) + 1.5 N₂(g)

2. 79.3g

Explanation:

<em>1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen.</em>

NaN₃(s) → Na(s) + 1.5 N₂(g)

<em>2. Suppose 43.0L of dinitrogen gas are produced by this reaction, at a temperature of 13.0°C and pressure of exactly 1atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits.</em>

First, we have to calculate the moles of N₂ from the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1atm.(43.0L)}{(0.08206atm.L/mol.K).286.2K} =1.83mol

The moles of NaN₃ are:

1.83molN_{2}.\frac{1molNaN_{3}}{1.5molN_{2}} =1.22molNaN_{3}

The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:

1.22mol.\frac{65.01g}{mol} =79.3g

5 0
3 years ago
This is a test please help
GenaCL600 [577]

Answer:

remaining still during the night.

Explanation:

3 0
2 years ago
Jim, Jill, Robert, and Kim each run paper chromatography on an unknown aqueous mixture. Jim gets a red band and a blue band, Jil
Romashka-Z-Leto [24]

Answer:

Robert

Explanation:

There is not more than one colour

4 0
2 years ago
A balloon occupies a volume of 2.00 l at 40.0oc. how much volume will it occupy at 30.0oc?
hodyreva [135]
<span>Charles' law says "at a constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature".

V </span>α T

Where V is the volume and T is the temperature in Kelvin of the gas. We can use this for two situations as,
V₁/T₁ = V₂/T₂

V₁ = 2.00 L
T₁ = 40.0 ⁰C = 313 K
V₂ = ?
T₂ = 30.0 ⁰C = 303 K

By applying the formula,
2.00 L / 313 K = V₂ / 303 K                   
                   V₂ = (2.00 L / 313 K) x 303 K
                   V₂ = 1.94 L

Hence, the volume of the balloon at 30.0 ⁰C  is 1.94 L
7 0
3 years ago
What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mol-1; (ΔHof of C6H6(g
wolverine [178]

Answer:

-608KJ/mol

Explanation:

3 C2H2(g) -> C6H6(g)

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= ΔHC6H6 - 3ΔHC2H2

ΔHrxn = 83 - 3(230)

ΔHrxn = -608

6 0
3 years ago
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