Answer:
Formular = C₅H₁₁NO₃
Explanation:
The empirical formular is the simplest formular of a compound can have.
We use the steps below to obtain the empirical formular;
Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.
Carbon = 45.46% = 45.46g
Hydrogen = 7.63% = 7.63g
Nitrogen = 10% = 10g
Oxygen = 100% - (45.46% + 7.63% + 10%) = 36.31% = 36.31g
Step 2: Determine the number of moles of each type of atom present.
Molar amount (M) = m/atomic mass
Carbon = 45.46 / 12 = 3.7883
Hydrogen = 7.63 / 1 = 7.63
Nitrogen = 10 / 14 = 0.7143
Oxygen = 36.91 / 16 = 2.3069
Step 3: Divide the number of moles of each element by the smallest number of moles. Smallest = 0.7143
Carbon = 3.7883 / 0.7143 = 5.3035
Hydrogen = 7.63 / 0.7143 = 10.67
Nitrogen = 0.7143 / 0.7143 = 1
Oxygen = 2.2693 / 0.7143 = 3.1770
Step 4: Convert numbers to whole numbers
Carbon = 5
Hydrogen = 11
Nitrogen = 1
Oxygen = 3
Formular = C₅H₁₁NO₃
