answer:
ionic bonds form between oppositely charged ions
explanation:
- an ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.
- ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal.
- a covalent bond involves a pair of electrons being shared between atoms.
There are two iron atoms and three oxygen atoms in each molecule of Fe2O3. So that's five atoms per molecule.
One mole of any molecular substance contains <span>6.02×1023</span> molecules. Since there are two iron atoms in each of the molecules we're considering, there will be <span><span>(6.02×1023)</span>⋅2=1.204×1024</span> iron atoms in a whole mole of them.
But we're considering 0.550 mol, so multiply by 0.550:
<span>n=(0.550</span> mol<span>)⋅<span>(3.01×1024</span></span> atoms/mol<span>)=6.62×1023</span> iron atoms.
The major product obtained when 1-hexyne is treated with H2 and Pd is; 1-hexene.
The structure of 1-hexyne is such that it possesses a triple bond around its first Carbon in it's carbon chain.
On this note; hydrogenation by treatment with H2 and Paladium, Pd as catalyst yields 1-hexene as the major product.
PS: Paladium, Pd is the major constituent of the Lindlar's catalyst.
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brainly.com/question/18915727
1) Answer is: pH = 3,44.
c(H₃O⁺) = 3,6·10⁻⁴ M = 3,6·10⁻⁴ mol/L = 0,00036 mol/L.
pH = -logc(H₃O⁺).
pH = -log(0,00036 mol/L).
pH = 3,44.
When pH is less than seven (pH<span><), solution is acidic (like this example).
</span>When is equal seven (pH = 7), solution is neutral.
When pH is greater than seven (pH <span>> 7), solution is basic.
</span>
2) Answer is: volume of H₂SO₄ is 5,75 mL.
Chemical reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.
c(H₂SO₄) = 0,2 M = 0,2 mol/L.
V(NaOH) = 23 mL = 0,023 L.
c(NaOH) = 0,1 M = 0,1 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,1 mol/L · 0,023 L.
n(NaOH) = 0,0023 mol.
From chemical reaction: n(H₂SO₄) : n(NaOH) = 1 : 2.
n(H₂SO₄) = 0,00115mol.
V(H₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).
V(H₂SO₄) = 0,00115 mol ÷ 0,2 mol/L.
V(H₂SO₄) = 0,00575 L = 5,75 mL.
3) c₁(solution) = 0,011 M = 0,011 mol/L.
V₁(solution) = 800 mL = 0,8 L.
M(methylene blue - C₁₆H₁₈ClN₃S) = 319,85 g/mol.
n₁ = c₁ · V₁.
n₁ = 0,011 mol/L · 0,8 L.
n₁ = 0,0088 mol.
m(C₁₆H₁₈ClN₃S) = 0,0088 mol · 319,85 g/mol.
m(C₁₆H₁₈ClN₃S) = 2,814 g.
m(C₁₆H₁₈ClN₃S) = 2,814 g · 1000mg/g = 2814 mg.
V = n ÷ c
V₂ = 0,0088 mol ÷ 0,001 mol/L = 8,8 L = 8800 mL.
V₃ = 0,0088 mol ÷ 0,00075 mol/L = 11,73 L = 11730 mL.
4) The normality or the equivalent concentration:
Cn(KH₂PO₄) = 0,02 N = 0,02 eq/L (<span>equivalent per liter).
</span>V(KH₂PO₄) = 0,125 L.
number of equivalents of solute = Cn(KH₂PO₄) · V(KH₂PO₄).
number of equivalents of solute = 0,02 eq/L · 0,125 L.
number of equivalents of solute = 0,0025 eq.
equivalent weight = M(KH₂PO₄) ÷ number of equivalents per mole of solute.
equivalent weight = 136,1 g/mol ÷ 1 eq/mol.
equivalent weight = 136,1 g/eq.
