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3 years ago

How is speed represented on a speedometer ? how is acceleration represented?

1 answer:

8 0

Speed is scalar quantity that is defined only by its magnitude and is represented with one value.
Velocity on the other side is a vector quantity that is defined with its magnitude and direction. The speedometer measures and displays the speed of the vehicle.
Where the needle points on the speedometer that is the speed of the vehicle.
The velocity is not explicitly shown, but if f the needle is moving<span>, you can get a rough idea of acceleration. If the needle is going clockwise the vehicle is accelerating.</span>

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All 2023 ariya ac synchronous drive motors produce ____% torque at 0 mph for impressive off-the-line acceleration and smooth cru

Savatey [412]

All 2023 Ariya ac synchronous drive motors produce 100% torque at 0 mph for impressive off-the-line acceleration and smooth cruising.

<h3>How to calculate the torque?</h3>

Mathematically, the torque of an automobile vehicle can be calculated by using this formula:

Torque = Fd

<u>Where:</u>

F is the force.

d is the distance.

Generally, torque is a rotational force which is developed by the crankshaft of an automobile vehicle and its capacity to move at a specific acceleration.

Read more on torque here: brainly.com/question/14839816

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2 years ago

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

lisabon 2012 [21]

$v ^{2}$ = Joules ÷ (0.5×Kilograms)

14J ÷ 8.5 = 1.64705882

Remember, 1.64705882 = v², so we need to find the square root.

The square root of 1.64705882 is 1.283377894464448

Hope this helps!

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3 years ago

Read 2 more answers

Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?

Step2247 [10]

Visible light waves are the type of electromagnetic waves that make up the colors of the rainbow, because the rainbow is visible to us.

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3 years ago

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Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance $D_{A}$ beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed $v_{A}$ . Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed $v_{B}$ , which is greater than $v_{A}$ .

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: $t=\frac{D_{A}}{v_{B}-v_{A}}$

Part B: $x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

$x=x_{0}+vt$

where

$x_{0}$ is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is $D_{A}$ .

The equation will be:

$x_{A}=D_{A}+v_{A}t$

Car B started at the starting line. So, its equation is

$x_{B}=v_{B}t$

Part A: When they meet, both car are at "the same position":

$D_{A}+v_{A}t=v_{B}t$

$v_{B}t-v_{A}t=D_{A}$

$t(v_{B}-v_{A})=D_{A}$

$t=\frac{D_{A}}{v_{B}-v_{A}}$

Car B meet with Car A after $t=\frac{D_{A}}{v_{B}-v_{A}}$ units of time.

Part B: With the meeting time, we can determine the position they will be:

$x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )$

$x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$

Since Car B started at the starting line, the distance Car B will be when it passes Car A is $x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$ units of distance.

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2 years ago

Question 9:<br> All parts thank you !

WINSTONCH [101]

Photo Math is the answer

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3 years ago