Given:
A compound with:
Number of carbon atoms = 9
Number of double bonds = 1
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left
Try to illustrate the given and observe the formation of the atoms. Now, follow the correct IUPAC naming system. The name of the compound is
4-propyl-1-hexene
Count from the right to the left, the double bond is between the 1st and 2nd carbon, thus, 1-hexene. The propyl branches out the 4th carbon from the right, thus 4-propyl.
The correct answer is 0.16138
<u>Solution:</u>
Percentage transmission (%T) of the sample = 15.6
Therefore, Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
<u>Use Beer’s law:</u>
A = ε*c*l where ε = molar absorptivity of the solution, c = concentration of the solution, and l = path length of the solution.
Given A = 0.8069 and l = 5.00 cm, we must have
<u>0.8069 = ε*c*(5.00 cm)</u>
ε*c = 0.16138 cm-1
For the next part, assume that ε*c remains constant and we have
A’ = ε*c*l’ where l = 1.00 cm.
Plug in values and write
A’ = (0.16138 cm-1)*(1.00 cm) = 0.16138
The ratio of the light intensity entering the sample to the light intensity exiting the sample at a particular wavelength is defined as the transmittance. Absorption and transmission are two related and different quantities used in spectroscopy. The main difference between absorption and transmission is that absorption measures how much incident light is absorbed as it travels through the material, while transmission measures how much light is transmitted.
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Answer:
D. It is extremely reactive.
Explanation:
Potassium has atomic number of 19 and belongs to the group 1 elements.
A. It is dull and brittle
This is not true as potassium is a metal with a silver lustre.
B. It is not reactive
This is false. Because it is a group 1 element, it would readily lose it's electron to achieve octet configuration making it a reactive metal.
C. It is white and hard.
Potassium is a white metal, however it is not hard. Rather it is soft.
D. It is extremely reactive.
This is correct. Because it is a group 1 element, it would readily lose it's electron to achieve octet configuration making it a reactive metal.
4. The particles found outside the nucleus are the electrons.