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evablogger [386]
3 years ago
12

Why is DNA important in living organisms?​

Chemistry
1 answer:
Marianna [84]3 years ago
5 0

Answer:

DNA is a vital for all living beings even plants.

Explanation:

It is important for inheritance, coding for proteins and the genitic instruction guide for life and its processes. DNA holds the instruction for an organisms or each cells development and reproduction and ultimately death.

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How can an iceberg (temperature=0 Celsius) have more energy than a burning match head (temperature=230 Celsius)?
jok3333 [9.3K]
Temperature is the average energy of each particle and does not really give you an indication of the total internal energy.  That being said, total internal energy is the sum of all of the molecule's energy in a given object so it would make sense that an ice berg (having a huge number molecules at a lower average energy) would have more internal energy than a match head (having a much smaller number of molecules at a higher average energy).  Basically, the fact that ice bergs tend to be huge and contain much more molecules than a match head, means that ice bergs can have a larger total internal energy which means they store more energy.

I hope this helps.
5 0
3 years ago
How can you tell whether a fat contains primarily saturated or unsaturated fatty acids?
Romashka-Z-Leto [24]
In terms of physically observing it, if the substance is a lions based substance, like oil or margarine, depending on the state, this will inform how well the hydrocarbons can pack together well or not, or will there be bends in the ring preventing the molecules from packing well.

Liquids are unsaturated
Solids are saturated.
3 0
3 years ago
Rontloc pestu (Scrambled word)
lianna [129]
Is it "control setup"?
5 0
3 years ago
Read 2 more answers
It is necessary to have a 40% antifreeze solution in the radiator of a certain car. the radiator now has 70 liters of 20% soluti
Akimi4 [234]
The answer is : 17.5 liters drained and replaced by 17.5 liters of 100% solution. 
x = amount drained and replaced
(70-x) = remaining amount of 20% solution
<span>.20(70-x) + 1.00(x) = .40(70)
14 - .2x + 1x = 28
1x - .2x = 28 - 14
</span><span>.8x = 14
</span><span>x = 14/.8
x= 17,5 ( 17.5 liters drained and replaced by 17.5 liters of 100% solution)

</span>
6 0
3 years ago
Read 2 more answers
Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0
3 years ago
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