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Alenkasestr [34]
4 years ago
9

In 1906, there was a small population of deer on the Kaibab Plateau. Because cows had overgrazed the food on the Kaibab Plateau,

the Forest Service decided to create a preserve on the Kaibab Plateau for the deer. In the preserve, the cows and the natural predators of the deer were removed. In 1920, the Forest Service discovered that the number of deer in the preserve was very large. By 1923, most of the deer were starving from a lack of food. Which statement best describes what happened on the Kaibab Plateau between 1906 and 1923? Overgrazing by cows caused the deer on the Kaibab Plateau to starve. The large growth and starvation of the deer population was an event of natural selection. With no natural predators to regulate the population, the deer population continued to grow. The growth of the deer population was slower than the growth of the food supply on the Plateau, causing starvation.
Chemistry
1 answer:
RideAnS [48]4 years ago
5 0

Answer: With no natural predators to regulate the population, the deer population continued to grow.

Explanation:

In 1906 a preserve was created for the deer. In creating this they drove both the cows as well as the deer's natural predators away. This meant that the deer population was no longer regulated by the predators hunting and eating them which led to an explosion in deer population.

The land which had been overgrazed at some point could not support this population and so the deer started starving because there simple wasn't enough food to support their population.

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The nervous systems consists of the brain and the...........
Artist 52 [7]

Answer:

spinal cord

Explanation:

The nervous system has two main parts: The central nervous system is made up of the brain and spinal cord.

7 0
3 years ago
what is the wavelength of a photon emitted when an electron jumps from n=2 to n= 1 energy level of a single ionized helium atom
Neko [114]

Answer:

I hope it help you the wavelength is 1.9130E-28

7 0
3 years ago
If the balloon had a volume of 3 L at a depth of 50 m, what was the original volume of the balloon it we assume the pressure at
disa [49]

If the balloon had a volume of 3 L at a depth of 50 m, the original volume of the balloon will be

<h3 /><h3>What is Significant figures ?</h3>

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the atmospheric pressure.

The hydrostatic pressure P of a liquid is given by the formula ;

P = ρgh

where,

  • ρ = the density of the liquid (Density of water = 1000 kg m⁻³)
  • g = the acceleration due to gravity (9.81 ms⁻²)
  • h = the depth of the liquid (Given : 50 m)

P =  1000 kg m⁻³ x 9.81 ms⁻² x 50 m

   = 1000 kg m⁻¹ x 9.81 s⁻² x 50

   = 4.9 x 10⁵ Pa

Lets's Convert Pa in to atm

    =   4.9 x 10⁵ Pa x 1 / 103. 325 x 10³ Pa

    = 4.7 atm

Mow, lets calculate P(atm) ;

P(atm) = 14.7 psi x 1 atm / 14.7 psi

          = 1 atm

Total Pressure at 50 m is ;

P(total) = 4.7 atm + 1 atm

            = 5.7 atm

Now we can apply Boyle's Law to calculate the volume of the balloon at the surface.

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

According to the question ;

  • P₁ = 5.7 atm  
  • P₂ = 1 atm
  • V₁ = 3 L
  • V₂ = ?

V₂ = 3 L x 5.7 atm  / 1 atm

     = 17.1 L

     = 20 L ( 1 significant figure)

Learn more about Boyles law here ;

brainly.com/question/1437490

#SPJ1

8 0
2 years ago
A substance has a mass of 100 g and a volume of 10 mL. What is the
Marysya12 [62]

Answer:

<h2>10 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

denstity =  \frac{100}{10}  \\

We have the final answer as

<h3>10 g/mL</h3>

Hope this helps you

5 0
3 years ago
A 544 mg of a mixture of fluorene and benzoic acid was weighed out and subjected to an extraction and recrystallization. After t
butalik [34]

<u>Answer:</u> The percent composition of fluorene is 33.08 % and benzoic acid is 36.03 %.

<u>Explanation:</u>

We are given:

Mass of mixture = 544 mg

Mass of fluorene after purification = 1.80\times 10^2mg=180mg

Mass of benzoic acid after purification = 196 mg

To calculate the percentage composition of a substance in a mixture, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

<u>For fluorene:</u>

\%\text{ composition of fluorene}=\frac{180}{544}\times 100=33.08\%

Hence, the percent composition of fluorene is 33.08 %

<u>For benzoic acid:</u>

\%\text{ composition of benzoic acid}=\frac{196}{544}\times 100=36.03\%

Hence, the percent composition of benzoic acid is 36.03 %

5 0
4 years ago
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