We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K
Answer:
oxidation:Ti to Ti Reduction:O2 toO2
Explanation:
<em>oxidation loses electron while Reduction gains electron</em>
Answer:
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