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polet [3.4K]
3 years ago
6

14 1/5 - 5 5/6 as a fraction

Mathematics
2 answers:
melomori [17]3 years ago
4 0

Answer:

\frac{251}{30} or 8\frac{11}{30}

Step-by-step explanation:

nirvana33 [79]3 years ago
4 0

Answer:

8 11/30

Step-by-step explanation:

But all you have to do is just simplify you can use calculator soup to siplify I hope this helps.

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the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle
nikdorinn [45]
l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}
length\approx9.71cm;\ width\approx17.71cm
4 0
3 years ago
A large rock (mass = 4.0 kg) moving at a velocity of 2.0 m/s has a momentum of _______ kg*m/s
Elodia [21]

Step-by-step explanation:

❁ \underline{ \underline{ \text{Given} }}:

  • Mass of a large rock ( m ) = 4.0 kg
  • Velocity ( v ) = 2.0 m/s

❁ \underline{ \underline{ \text{ \: To \: find}}}:

  • Momentum ( p )

✑ \underline{ \underline{ \text{Solution}}} :

\boxed{ \underline{ \sf{Momentum \:  =  \: mass \:  \times  \: velocity}}}

plug the known values :

⟹ \sf{Momentum = 4.0 \: kg \:  \times  \: 2.0 \:m/s }

⟹ \sf{Momentum = 8 \: kg \: m/s}

\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer :   \bold{ \underline{8} }\: kg*m/s}}}}

⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆⋆

✑ \underline{ \underline{ \text{Learn \: more about \: momentum}}}:

Imagine that a car and a truck both have the same speed on the road. Which one can stop easily ? Of course , it is hard to stop the truck relative to the car. The reason is that the car and the truck have the same speed bit different masses. Thus , we can say that to stop a heavier body is harder than to stop a lighter one even both of them have the same speed.

If two tennis balls are hit towards you in different velocities , it is not equally easier to stop them. The ball in more velocity is difficult to stop relatively. Thus , we can say that to stop a body in more velocity is harder than to stop a body with less velocity , eventhough they have the same speed.

The physical quantity that describes the quantity of motion of a body is called momentum. The momentum of a moving body or linear momentum is defined as the product of mass & velocity of a moving body.

Mathematically ,

Momentum = mass × velocity

i.e p = m × v

The SI unit of momentum is kg • m/s. Since velocity is a vector quantity and multiplied with mass ( scalar quantity) , momentum becomes a vector quantity. Direction of momentum is the same as velocity.

Hope I helped ! ♡

Have a wonderful day / night ツ

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7 0
3 years ago
Determine if the following system of equations has no solutions, infinitely many
FrozenT [24]

Answer:

infinitely many solutions

Step-by-step explanation:

x + 6y = -5

3x + 18y = -15

Multiply the first equation by 3

3(x + 6y) = -5*3

3x + 18y = -15

The two equations are identical.  This means they have infinite solutions along the line x+6y = -5

8 0
3 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
3 years ago
What is the equation for the line that passes through (3, 2) and has a slope<br> equal to 1/3
lana66690 [7]

Answer:

y=1/3x+1

Step-by-step explanation:

6 0
3 years ago
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