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3 years ago

Is energy transformation from potential to kinetic 100%?

1 answer:

8 0

Yes. take a bow for instance. while pulling back the string you have potential energy. when you let the string go and the arrow flies towards your target the string is filled with kinetic energy.

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mote1985 [20]

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2 years ago

PLEASE HELP

Sergeu [11.5K]

The vertical component of the initial velocity is $v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is $v_0_x = \frac{x}{t}$

The horizontal displacement when the object reaches maximum height is $X = \frac{xy}{gt^2} + \frac{x}{2}$

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

$y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is calculated as;

$x = v_0_xt\\\\v_0_x = \frac{x}{t}$

The time to reach to the maximum height is calculated as;

$T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T = \frac{1}{g} (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t$

The horizontal displacement when the object reaches maximum height is calculated as;

$X= v_0_x \times T\\\\X= \frac{x}{t} \times (\frac{y}{gt} + \frac{1}{2} t)\\\\X = \frac{xy}{gt^2} + \frac{x}{2}$

Learn more here: brainly.com/question/20689870

8 0

3 years ago

15. You are watching a baseball game on television that 15

Gre4nikov [31]

Answer:

t_total = 6.99 s

Explanation:

It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is

t_total = t₁ + t₂ + t₂

we look for t1, it indicates that the distance x = 22m

v = x / t

t = x / v

t₁ = 22/343

t₁ = 6.41 10-2 s

time t₂

t₂ = 4500 103/3 108

t₂ = 1.5 10-5 s

time t₃

t₃ = 2/343

t₃ = 5.83 10⁻³

Total time is

t_total = t₁ + t₂ + t₃

t_total = 6.41 10⁻² + 1.5 10⁻⁵ + 0.583 10⁻²

t_total = 6.99 s

5 0

3 years ago