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Cloud [144]
3 years ago
7

Is energy transformation from potential to kinetic 100%?

Physics
1 answer:
Arada [10]3 years ago
8 0
Yes. take a bow for instance. while pulling back the string you have potential energy. when you let the string go and the arrow flies towards your target the string is filled with kinetic energy.
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A large truck is moving 22.0 m/s. If it’s momentum is 125,000 kg • m/s, what is the trucks mass
strojnjashka [21]

Answer:

p = mv

m = p/v = 125000/22 = 5682 kg

Explanation:

Direct application of the momentum equation

p = mv

where,

p: momentum

m: mass

v: object velocity

steps:

-------

1) check for units consistency (  SI or Imperial)

2) separate the variable you are looking for.

3) DONE! :DD

6 0
3 years ago
PLZ HELP
serg [7]

The definition of speed is (distance covered) / (time to cover the distance) .

So a unit of speed has to be (a unit of length) / (a unit of time) .

Here are several perfectly fine units of speed:

-- miles per hour

-- feet per second

-- meters per second

-- kilometers per hour

-- inches per second

-- centimeters per minute

-- yards per Century

-- furlongs per fortnight

-- nanometers per microsecond

-- Smoots per week

-- parsecs per millenium

8 0
3 years ago
A power plant needs to slow down the fission reactions in its nuclear reactor. In which direction should the uranium-containing
ohaa [14]

Answer:

It's D) Down that's what i got in e2020

8 0
3 years ago
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If one wall of a room consists of a large flat mirror, how much larger will the
kiruha [24]

Answer:

The room will appear to be twice as big because the object distance is equal to the image distance. The mirror takes into account the distance between the mirror and how big the room is.

8 0
3 years ago
You lower the temperature of a sample of liquid carbon disulfide from 90.3 ∘ C until its volume contracts by 0.507 % of its init
Lady_Fox [76]

Answer:

T_{f} = 85.89 ° C

Explanation:

The linear thermal expansion process is given by

      ΔL = L α ΔT

For the three-dimensional case, the expression takes the form

     ΔV = V β ΔT

Let's apply this equation to our case

     ΔV / V = ​​-0.507% = -0.507 10-2

     ΔT = (ΔV / V)  1 /β

     ΔT = -0.507 10⁻²  1 / 1.15 10⁻³

     ΔT = -4.409

     T_{f} –T₀ = 4,409

     T_{f} = T₀ - 4,409

     T_{f} = 90.3-4409

     T_{f} = 85.89 ° C

6 0
3 years ago
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