1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
7

the gravitational force between two masses at distance of 2.5×10^6 metre is 250 Newton . what should be distance between them to

reduce the gravitational force by half?​
Physics
2 answers:
Aleks04 [339]3 years ago
7 0

Answer:

<u>distance</u><u> </u><u>between</u><u> </u><u>should</u><u> </u><u>be</u><u> </u><u>1</u><u>.</u><u>2</u><u>5</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>^</u><u>6</u><u> </u><u>m</u>

Explanation:

Force is proportional to separation distance.

250 \: newtons = 2.5 \times  {10}^{6}  \: metres \\ ( \frac{1}{2}  \times 250) \: newtons = d \\  \\ d =  \frac{125 \times 2.5 \times  {10}^{6} }{250}  \\ d = 1.25 \times  {10}^{6}  \: metres

solmaris [256]3 years ago
3 0

Answer:

distance between should be 1.25×10^6.

Explanation:

force Is proportional to separation .

mrk above answer branilest .

You might be interested in
in the derivation of the time period of a pendulum in electric field when considering the fbd of bob to find the g effective why
Neko [114]

Answer:

we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.

The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.

that's what I know so far

8 0
3 years ago
A wave hits a wall as shown. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction
dangina [55]
The answer is reflection.

The drawing is simple but illustrates the concept beautifully.
8 0
3 years ago
Read 2 more answers
A rocket is fired at 100 m/s at an angle of 37, what was its speed at the top of its path?
Nadusha1986 [10]

Answer:

0m/s

Explanation:

Since its fired at an angle, at the top there will be a split second where the velocity will be 0, as it has a parabolic shape, so the speed at the top of its path is 0

4 0
3 years ago
if vector u has lenght 70 and direction 40 degrees, and vector v has length 85 and direction 335 degrees what is the length and
Anastaziya [24]

Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62

\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99

||v|| = 85

θ = 335°

\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03

\vec{v}_y=||v||sin\theta \\\Rightarrow \vec{v}_y=85sin335=-35.92

Resultant

R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15

\theta=tan^{-1}\frac{R_y}{R_x}\\\Rightarrow \theta=tan^{-1}\frac{70sin40+85sin335}{70cos40+85cos335}\\\Rightarrow \theta=tan^{-1}0.069=3.97^{\circ}

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

4 0
3 years ago
What part does infiltration play in the water cycle?
ELEN [110]
Nfiltration is the movement of surface water into rock or soil through cracks and pore spaces.
8 0
3 years ago
Other questions:
  • An object acted on by three forces moves with constant velocity. one force acting on the object is in the positive x direction a
    8·1 answer
  • A bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. The distance from the windowsill to the g
    14·2 answers
  • A car travels a distance of 320 km in 4 hours. What is your average speed in meters per second?
    8·1 answer
  • Topic: Chapter 10: Projectory or trajectile?
    13·1 answer
  • An electric motor transforms potential energy into mechanical energy.<br>True or false ​
    7·2 answers
  • Please help me out. Convert 28 pints to cups. Using one step conversion.
    6·1 answer
  • How<br> to cheat vhhhhhhhhhhhhhhhhhhhh
    6·2 answers
  • Look at the image of a salad with chicken on a counter top .in which direction is the thermal energy moving?
    15·1 answer
  • ) A 73-mH solenoid inductor is wound on a form that is 0.80 m long and 0.10 m in diameter. A coil having a resistance of is tigh
    6·1 answer
  • In comparing molar specific heat for gases under constant pressure CP and constant volume CV, we conclude that (more than one co
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!