Answer:
The magnitude of the acceleration of the box is
.
Explanation:
The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:


From second equation of equilibrium we find an expression for the normal force and find the respective value:



Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:



The magnitude of the acceleration of the box is
.
Answer:
(a) -202 m/s²
(b) 198 m
Explanation:
Given data
- Initial speed (v₀): 283 m/s

- Final speed (vf): 0 (rest)
(a) The acceleration (a) is the change in the speed over the time elapsed.
a = (vf - v₀)/t = (0 - 283 m/s)/ 1.40s = -202 m/s²
(b) We can find the distance traveled (d) using the following kinematic expression.
y = v₀ × t + 1/2 × a × t²
y = 283 m/s × 1.40 s + 1/2 × (-202 m/s²) × (1.40 s)²
y = 198 m
First of all the kinetic energy is when the particles move in continuous random motion.
If the temperature is high the colliding particles will collide more. and if the temperature is low the colliding particles will collide less.
Low temperature result in low kinetic energy
High temperature result in high kinetic energy
Absolute zero is the point where where all molecules have no kinetic energy. It is a theoretical value (it has never been reached).
The Kelvin temperature scale is based on absolute zero being the lowest possible temperature that could theoretically be reached. That is why there is no such thing as a negative Kelvin temperature value.
The answer is A. the fields lines never cross, if you bring another magnet near it, the lines work just compress