8 not counting Pluto 9 if counting Pluto, Pluto is technically not a planet anymore so best dentures 8.
If there was no friction the car will continue to move at a constant speed in a straight line.
The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 373.8 N.
<h3>What is the force required to support the weight on piston 2?</h3>
The force, F required to support the weight on piston 2 is calculated as follows:
f = 991 * 9.81 = 9721.71 N
A₂ = (9.46/2)² = 22.373
A₁ = (1.87/2)² = 0.874
F = 9721.71 * 0.874/22.373
F = 373.8 N
Inc conclusion, a smaller force is applied to lift the larger force at Piston 2.
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Water evaporates at 100⁰C
So change in temperature = 100-20 = 80⁰C
Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg
Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg
So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ
So amount of heat require to evaporate water = 334.88 kJ
a. The force applied would be equal to the frictional
force.
F = us Fn
where, F = applied force = 35 N, us = coeff of static
friction, Fn = normal force = weight
35 N = us * (6 kg * 9.81 m/s^2)
us = 0.595
b. The force applied would now be the sum of the
frictional force and force due to acceleration
F = uk Fn + m a
where, uk = coeff of kinetic friction
35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)
uk = 0.533
