Answer:
the inductive reactance of the coil is 1335.35 Ω
Explanation:
Given;
inductance of the coil, L = 250 mH = 0.25 H
effective current through the coil, I = 5 mA
frequency of the coil, f = 850 Hz
The inductive reactance of the coil is calculated as;
Therefore, the inductive reactance of the coil is 1335.35 Ω
Well you didnt give us any options to choose from
but my guess is that it has to do with erosion caused by the water
'A' is the false one, but 'C' is also so poorly worded that it's misleading.
Answer:
Explanation:
reactance of inductor = wL = 2 X 3.14 X 60 X 1.2 X 10⁻³ = .45 ohm.
reactance of capacitor = 1/wC = 1/( 2 X 3.14 X 60 X 1.8 X 10⁻⁶ ) = 1474.4
Impedence of the circuit =[ R² + ( I/wC - wL) ]¹/² = [250² + ( 1474.4-.45 )]¹/²
Impedence = 1495 ohm.
RMS Voltage = 120/ 1.414 = 84.86 V
current = 84.86 / 1495 = 0.0576
Potential over resistance = 0.0576 x 250 = 14.2 V.