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3 years ago

Solve: 3x+5=14 Find the value of x

Mathematics

2 answers:

Levart [38]3 years ago

7 0

$3x+5=14 \\ 3x=14-5 \\ 3x=9 / :3\\ \boxed{x=3} \\ \\\\\huge\text{The answer is x=3}$

-Dominant- [34]3 years ago

4 0

X=3

subtract 5 from both sides;
3x=9
divide both sides by 3;
x=9

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An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How

Nitella [24]

Answer:

There will be 916 ants alive after 4 months.

Step-by-step explanation:

Step 1

Let's change the percentage to a decimal by dividing by a 100.

6.5% / 100 = .065

Step 2

So, for the first month we will multiply the initial amount of ants by .065 and this will give us the number of ants that die.

1200 * .065 = 78

This means that after the first month, 1200 - 78 = 1122 ants will be alive.

Step 3

Now for the second month: 1122 * .065 = 72.93 (rounded to 73)

1122 - 73 = 1049 ants will be alive

Step 4

For the third month 1049 * .065 = 68.185 (rounded to 68)

1049 - 68 = 981 ants will be alive

Step 5

For the fourth month 981 * .065 = 63.765 (rounded to 64)

981 - 64 = 916 ants will be alive

Hope this helps!

5 0

3 years ago

Read 2 more answers

I am faceing north west. if i turn 180 clockwise i will be facing what

DIA [1.3K]

Answer:

south

Step-by-step explanation:

it’s half way turn because 180 is half of one 360 and north is right across from south:)

8 0

3 years ago

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Pls owrk out the missing angle

Alik [6]

Answer:

125

Step-by-step explanation:

A full circle is 360°

80+85+70=235

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4 0

3 years ago

Can you please help me

yarga [219]

With pleasure. broooooo

8 0

3 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago