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kakasveta [241]
3 years ago
15

In order to determine how much paint he needs to paint the front of his house, Joe is calculating the area he’ll be painting (th

e shaded region). The door is 7 feet by 3 ft. The large window is 5 ft by 3 ft. Each small window is 2 ft by 3 ft. Show work

Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer:

I found a matching diagram to the question online:

The area to be painted = 464.5 ft²

Step-by-step explanation:

Total area of the figure = area of the rectangle + area of the triangle.

Area of rectangle = Length × Breadth

Length = 25ft

Breadth = 15ft

Area of rectangle = 25 × 15 = 375 ft²

Note that we will subtract the unshaded regions because he will be painting the shaded regions only.

Area of door = 7 × 3 = 21 ft²

Area of large window = 5 × 3 = 15 ft²

Area to be painted on rectangle = total area - area of door - area of large window

= 375 - 21 - 15 = 339 ft²

Next let us solve for the triangle:

Area of triangle = 1/2 base × height

base = 25 ft

height = 26 - 15 = 11 ft

∴ Area of triangle = 0.5 × 25 × 11 = 137.5 ft²

Remember that we will subtract the area of the unshaded part.

unshaded region = 2 small windows

Areas of two small windows = 2 × ( 2 × 3) = 2 × 6 = 12 ft²

Therefore area of shaded portion of triangle = 137.5 - 12 = 125.5 ft²

Total area to be painted = shaded areas of (rectangle + triangle)

= 339 + 125.5 = 464.5 ft²

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d = 3 + at^2

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d - 3 = at^2

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t = √d - 3/a

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Andrew [12]
No because the extra 10% is off the discounted price, not the original. image that the CD originally cost $10. 15% off of the CD would make the price $8.50. Another 10% off of $8.50 would make the price that you have to pay $7.65. 25% off of the original price of $10 would make the price $7.50. Sorry if its a bit confusing but I hope that helps! 
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3 years ago
Sandra bought 4 bars of chocolate and a packet of nuts for $11.50. If a bar of chocolate costs $0.50 less than a packet of nuts,
Luden [163]

Answer:

A packet of nuts costs $2.70

Step-by-step explanation:

Let C represent the cost of a bar of chocolate and P represent the cost of a packet of nuts

4 bars of chocolate will cost $4C

1 packet of nuts costs $P

Total price Sandra paid is $11.50

This can be represented using

4C + P = 11.50    (1)

A bar of chocolate costs $0.50 less than a packet of nuts. So

P - C =0.50  

-C + P = 0.50   (2)

Multiply eq (2) by 4 to get

-4C + 4P = 4 x 0.50

-4C + 4P = 2   (3)

Add equations (1) and (3) to eliminate the 4C term

4C + P - 4C + 4P = 11.50 + 2

P+4P = 13.50

5P = 13.50

Dividing by 5 on both sides

5P/5 = 13.50/5

P = 2.70

So a packet of nuts costs $2.70  (Answer)

To verify this is correct,

Use equation (2) to get

-C + P = 0.50

-C + 2.70 = 0.50

Add C to both sides

-C + 2.70 + C = 0.50 + C

2.70 = 0.50 + C

Subtract 0.50 from both sides

2.70-0.50 = 0.50 + C - 0.50

2.20 = C which is C= 2.20

Plug this value into equation (1)

4(2.20) + 2.70 = 8.80 + 2.70 = 11.50

So verified that answers are correct

8 0
1 year ago
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