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ASHA 777 [7]
3 years ago
12

Add: 25 + |-14| + 3

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

42

Step-by-step explanation:

25+14+3= 42

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Please help! What's the area of this triangle? (Please put an answer that helps...)
LenKa [72]

Answer:

5

Step-by-step explanation:

see attachment below

3 0
3 years ago
Let u=  (-1,3) and w =(2,4) Find the resulting vector of 2u-4w  in component form..
IgorLugansk [536]
Very simple. You just use the vectors as normal numbers, and multiply the coordinates with 2 and 4 like this: 

2*u = 2* (2,4) = (4,8)
4*w = 4* (-1,3) = (-4,12)

(4,8) - (-4,12) = (8,-4)

So the vector has the coordinates (8,-4)

7 0
4 years ago
Read 2 more answers
What is the GCF of 72 and 36​
EleoNora [17]

Answer:

36

Step-by-step explanation:

GCF or greatest common factor is the greater/biggest number that can factor for both numbers. To find GCF, you need to make factor of both number

72- 2 * 2 * 2 * 3 * 3 = 2^3 * 3^2

36= 2 * 2 * 3 * 3      =  2^2 * 3^2  

After this, you can compare the factor of both numbers. Both numbers can be divided by 2, but 36 can be divided 2 times while 72 can be divided 3 times. In this case, you take the lowest number which is 2. Both numbers can be divided by 3^2 so you can take it whole.

The factor will be: 2^2 * 3 *2= 4 * 9= 36

7 0
3 years ago
Can anyone please help me with questions 27 & 29 PLEASE
nataly862011 [7]

Answer:

Anser 29:Population density refers to the number of people who live in a defined land area (usually square miles or square kilometers). So, if two million people live in ten square miles, the population density is two hundred thousand people per square mile

Answer 29: 100,000 times per day, and about 35 million times in a year.And 60 to 100 times in a minute

Step-by-step explanation:

8 0
3 years ago
Following are measurements of soil concentrations (in mg/kg) of chromium (Cr) and nickel (Ni) at 20 sites in the area of Clevela
WINSTONCH [101]

Answer:

a) see attached

b) see attached

Step-by-step explanation:

There is existence of outlier in the Ni data and there is none is Cr data.

########################################

# You can try this out in R programming

cr = c(34, 1, 511, 2, 574, 496, 322, 424, 269, 140, 244, 252, 76, 108, 24,

38, 18, 34, 30, 191)

Ni = c(23, 22, 55, 39, 283, 34, 159, 37, 61, 34, 163, 140, 32,

23, 54, 837, 64, 354, 376, 471)

par(mfrow=c(1,2))

hist(cr, col='green')

hist(Ni, col='brown')

par(mfrow=c(1,2))

boxplot(cr, main = 'Boxplot of Cr')

boxplot(Ni, main = 'Boxplot of Ni')

boxplot(cr, Ni)

7 0
3 years ago
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