1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
4 years ago
14

Consider the reaction.

Chemistry
1 answer:
gayaneshka [121]4 years ago
6 0
<span>The answer is (D)-when the rate of the forward and reverse reactions are equal.</span>
You might be interested in
Use the periodic table to determine the electron configuration for dysprosium (Dy) and americium (Am) in noble-gas notation
sergij07 [2.7K]

Answer:

Dysprosium [Dy]=[Xe]4f^{10}6s^2

Americium [Am]=[Rn]5f^77s^2

Dysprosium is a chemical element with symbol Dy and atomic number of 66. It is a rare earth metal and as it contains partially filled f sub shells, it belongs to f block. Xe is the nearest noble gas and has atomic number of 54.

Americium is a chemical element with symbol Am and atomic number of 95. It is a rare earth metal and as it contains half filled f sub shells, it belongs to f block. Radon is the nearest noble gas and has atomic number of 86.

3 0
3 years ago
Read 2 more answers
Calculate the freezing point of a solution 1.25 g benzene (C6H6) in 125 g of chloroform (CHCl3).
posledela

Answer:

The freezing point for the solution is -64.09°C

Explanation:

This problem can be solved, by the freezing point depression. This colligative problem shows, that the freezing point of a solution is lower than the freezing point of pure solvent.

ΔT = Kf.  m

ΔT = T° freezing pure solvent - T° freezing solution

Kf = Cryscopic constant, for chloroform is 4.68

T°freezing pure solvent = -63.5°C

m is mol/kg of solvent → molality

Let's determine the moles of benzene

1.25 g / 78 g/mol = 0.0160 mol

Let's convert the mass of solvent to kg

125 g . 1kg / 1000 g = 0.125 kg

m = 0.0160 mol / 0.125 kg → 0.128 m

Let's go to the formula to replace the data

-63.5°C - T° freezing solution = 4.68 °C/m . 0.128 m

T° freezing solution = - (4.68 °C/m . 0.128 m + 63.5°C)

T° freezing solution = - 64.09°C

3 0
3 years ago
0.57 centimeter to meter
uysha [10]
If 100cm is 1 metre
Then 0.57 cm =

If less more divides,
Hence 100÷0.57 × 1



= 0.0057 Metres.
6 0
3 years ago
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (2005 K)
jolli1 [7]

Answer:

205K

Explanation:

The following were obtained from the question:

n = 4moles

P = 5.6atm

V = 12L

R = 0.082atm.L/Kmol

T =?

PV = nRT

T = PV/nR

T = (5.6 x 12)/ (4 x 0.082)

T = 205K

8 0
3 years ago
Which substance can not be decomposed by a chemical change?
slamgirl [31]
The answer is (2) Copper. Because copper is consist of atom. If it is decomposed, the atom will be changed. While chemical change is just the break down and form of chemical bonds between atoms. 
6 0
3 years ago
Other questions:
  • Calculate the moles of Cu in 7.4×1021 atoms of Cu.
    10·1 answer
  • Mass of a substance divided by unit volume is called
    11·1 answer
  • What is formed from 2 pieces of different metals stuck together lengthwise?
    11·1 answer
  • If you don't no the answer for sure please don't answee
    10·2 answers
  • Are Elements on the Period Table of Elements?<br> Yes or No?
    14·2 answers
  • Describe how an El Niño event affected weather, food production, water supply, or human health.
    10·2 answers
  • Determine the empirical formula of a compound containing 47.37 grams of carbon, 10.59 grams of hydrogen, and 42.04 grams of oxyg
    10·1 answer
  • Will GIVE BRAINLIST IF YOU ANSWER CORRECTLY Identity the type of reaction and balance the equation, including the states of matt
    5·1 answer
  • How many significant figures are contained in the quantity 14.00 mL?
    12·1 answer
  • Calculate 5.1234 + 0.033÷ 1.650 and report to the correct number of significant figures.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!