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3 years ago

Use the periodic table to determine the electron configuration for dysprosium (Dy) and americium (Am) in noble-gas notation

Chemistry

2 answers:

sergij07 [2.7K]3 years ago

3 0

Answer:

Dysprosium [Dy]= $[Xe]4f^{10}6s^2$

Americium [Am]= $[Rn]5f^77s^2$

Dysprosium is a chemical element with symbol Dy and atomic number of 66. It is a rare earth metal and as it contains partially filled f sub shells, it belongs to f block. Xe is the nearest noble gas and has atomic number of 54.

Americium is a chemical element with symbol Am and atomic number of 95. It is a rare earth metal and as it contains half filled f sub shells, it belongs to f block. Radon is the nearest noble gas and has atomic number of 86.

Alex3 years ago

3 0

Dy: [Xe]6s24f10

Am: [Rn]7s25f 7 :)

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55 L of a gas at 25oC has its temperature increased to 35oC. What is its new volume?

ladessa [460]

Answer:

Approximately 56.8 liters.

Assumption: this gas is an ideal gas, and this change in temperature is an isobaric process.

Explanation:

Assume that the gas here acts like an ideal gas. Assume that this process is isobaric (in other words, pressure on the gas stays the same.) By Charles's Law, the volume of an ideal gas is proportional to its absolute temperature when its pressure is constant. In other words

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}$ ,

where

$V_2$ is the final volume,
$V_1$ is the initial volume,
$T_2$ is the final temperature in degrees Kelvins.
$T_1$ is the initial temperature in degrees Kelvins.

Convert the temperatures to degrees Kelvins:

$T_1 = \rm 25^{\circ}C = (25 + 273.15)\; K = 298.15\; K$ .

$T_2 = \rm 35^{\circ}C = (35 + 273.15)\; K = 308.15\; K$ .

Apply Charles's Law to find the new volume of this gas:

$\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 55\;L \times \frac{308.15\; K}{298.15\; K} = 56.8\; L$ .

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3 years ago

This is the elliptical orbit of the Earth around the sun. It takes 365.26 days to complete one orbit.

nydimaria [60]

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Calculate the heat energy required to melt 4kg of ice when the specific latent heat of fusion of water is 334,000 J/kg.

Setler79 [48]

Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 $\frac{J}{kg}$ is 1,336 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat energy required to melt ice</h3>

In this case, you know:

m= 4 kg
L= specific latent heat of fusion of water= 334,000 $\frac{J}{kg}$

Replacing in the expression for latent heat:

Q = 4 kg× 334,000 $\frac{J}{kg}$

Solving:

<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)

Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 $\frac{J}{kg}$ is 1,336 kJ.

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2 years ago

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For which of the following molecular formulas is the formula shown in parentheses the correct empirical formula? (a) C12H22O11 (

Elodia [21]

Answer:

C₁₂H₂₂O₁₁ (C₁₂H₂₂O₁₁ ).

Explanation:

The empirical formula is obtained when we divide the molecular formula with a whole number giving the simplest ratio of all the elements (in whole number).

a) C₁₂H₂₂O₁₁ :

There is no number with which we can divide the ratio further to get a simpler formula hence the molecular formula of the given compound is the empirical formula of the compound. Hence it is correct.

(C₁₂H₂₂O₁₁),

(b) C₈H₁₂O₄

The empirical formula can be obtained by dividing the formula with "4"

The empirical formula would be

(C₂H₃O)

The empirical formula would be (H₁O₁)

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3 years ago

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