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jek_recluse [69]
3 years ago
13

Use the periodic table to determine the electron configuration for dysprosium (Dy) and americium (Am) in noble-gas notation

Chemistry
2 answers:
sergij07 [2.7K]3 years ago
3 0

Answer:

Dysprosium [Dy]=[Xe]4f^{10}6s^2

Americium [Am]=[Rn]5f^77s^2

Dysprosium is a chemical element with symbol Dy and atomic number of 66. It is a rare earth metal and as it contains partially filled f sub shells, it belongs to f block. Xe is the nearest noble gas and has atomic number of 54.

Americium is a chemical element with symbol Am and atomic number of 95. It is a rare earth metal and as it contains half filled f sub shells, it belongs to f block. Radon is the nearest noble gas and has atomic number of 86.

Alex3 years ago
3 0

Dy: [Xe]6s24f10

Am: [Rn]7s25f 7 :)

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tangare [24]

Answer:

In short, because we are tearing up the oxygen factories to make way for carbon dioxide emitters. (Doesn't make a lot of sense, read the explanation)

Explanation:

So, 1000 years ago, we had a lot more trees, didn't have engines or cars or factories or anything, really that released carbon dioxide into the air and we had a lot more trees and since the invention of cars, engines, carbon dioxide-emitting tools and factories and all the other things that emit "Greenhouse gases" and in doing that, cleared more trees to make room for factories and roads and that has drastically changed the outlook of the carbon cycle.

4 0
3 years ago
The amount of a harmful chemical to which a person is exposed is the ____.
kotykmax [81]
A. dose
a dose is an amount, a response is an action, and pollutant and toxins are substances
6 0
3 years ago
Read 2 more answers
9A. A sample of hydrogen at 1.56 atm had it's pressure decreased to 0.73
Jlenok [28]

Answer:idk

Explanation:

Idk

8 0
3 years ago
Which of the following isoelectronic series is correctly ranked from largest ionic radius to smallest ionic radius? 1. N 3−, O 2
love history [14]

Answer:

<u>Option 1</u>:  N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²    

Explanation:

<u>Ionic radius is the radius of an atom´s ion in ionic crystal structure</u>.<u> </u><u><em>In an ion that lose an electron, to form a cation, the radius of the ion gets smaller</em></u><em>, </em>because the repulsion between electrons decrease because fewer electrons are present. Conversely, <u><em>adding on electron to a neutral atom, to form an anion, causes electron - electron repulsions to increase, so the size of the radius of the ion gets bigger.</em></u>                  

<u><em>Isoelectronic species are ions or elements that have the same number of electrons in their electronic shells but have different overall charges, because of their different atomic numbers</em></u>.                        

<u><em>In a isolelectronic series (same number of electrons),</em></u> <u><em>the increase of the positive charge (given by the number of protons in the nucleus), will cause a decrease in radius </em></u>beacuse the greater electrostatic attraction between the electrons and the nucleus. Consequently, the ion with the greatest nuclear charge will have the smallest ionic radius and the ion with the smallest nulear charge will have the largest ionic radius.  

<u>We will use this principle to solve our problem</u>.  

In our case, the given ions are:  

  • N⁻³ :    Z = 7,  e⁻ = 10
  • O⁻²:     Z= 8,   e⁻ =10
  • F⁻:       Z = 9,  e⁻ = 10
  • Na⁺:    Z= 11,   e⁻ = 10
  • Mg⁺²:  Z=12,   e⁻ =10

where Z= number of protons, and e⁻ = number of electrons.

<em><u>Hence the decreasing order of ionic radius is:</u></em>

N⁻³ > O⁻² > F⁻ > Na⁺ > Mg⁺²  

Have a nice day!

4 0
3 years ago
Suggest two ways to liquefy the gases.
aleksandr82 [10.1K]
There are two ways to liquefy a gas:

-- Increase the pressure on it.

-- Lower its temperature.

The liquefication is faster and easier if you do both.
3 0
3 years ago
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