If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (2005 K)
1 answer:
Answer:
205K
Explanation:
The following were obtained from the question:
n = 4moles
P = 5.6atm
V = 12L
R = 0.082atm.L/Kmol
T =?
PV = nRT
T = PV/nR
T = (5.6 x 12)/ (4 x 0.082)
T = 205K
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