The answer is one solution
Answer: A. 3 ways: k, DE, ED (both DE and ED have line markers over top)
To name a line, we just need two points on the line. We list them in any order because the line extends forever in both directions. Contrast this with a ray where order does matter. The little k is another way to name a line, potentially simplifying things.
Choice B is close, but it mentions ray DE instead of line DE. Choice C is missing line ED. Choice D is a similar story as choice B. These facts allow us to rule out B through D.

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Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...

Multiply sides by -2 :


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Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...



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Step (3)



And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Step-by-step explanation:
so first you graph the triangle
count how many units one point is from the other point
and if it's hard to count the units (maybe bc the line is diagonal) use the distance formula or the Pythagorean theorem
Volume is a three-dimensional scalar quantity. The volume of the cube with side length of 4 inches is 64 inches³.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given the volume of a cube is the cube of the length of a side. If a side is S, the volume is S^3. Therefore, the volume of cube with side 4 inches will be,
Volume of the cube = (4 in)³ = 64 in³
Hence, the volume of the cube with side length of 4 inches is 64 inches³.
Learn more about Volume:
brainly.com/question/13338592
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