How many atoms of he gas are present in a 450 ml container at 35°c and 740 mmhg?

1 answer:

8 0

To answer this question, we will need to use the gas law which states that:
PV = nRT where:
P is the pressure of the gas = 740 mmHg = 98658.550357 Pascal
V is the volume = 450 ml = 0.45 liters
n is the number of moles that we will calculate
R is the gas constant = <span> 8.314 J/(K. </span>mol<span>)
T is the temperature = 35 celcius = 308 degrees kelvin

Substitute with these values in the above equation to get the number of moles as follows:
</span>98658.550357 * 0.45 = n * 8.314 * 308
n = 17.3375 moles

Each mole contains Avogadro's number of atoms, therefore:
number of atoms = 17.3375 * 6.02 * 10^23 = 1.0437 * 10^25 atoms

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How many moles are in 123.0g (NH4)2SO4

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Here you go! There are 0.9307 moles in 123.0 g of the compound. I solved this by using a fence post method. I calculated the number of grams in one mol of (NH4)2 SO4 and got 132.16.

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After that, i divided the given mass by the mass of one mol of the compound.

The answer is 0.9307 moles!! I hope this helped you! :))