How many moles are in 123.0g (NH4)2SO4
1 answer:
Here you go! There are 0.9307 moles in 123.0 g of the compound. I solved this by using a fence post method. I calculated the number of grams in one mol of (NH4)2 SO4 and got 132.16.
I did this by finding the atomic mass of each element on the periodic table (my work is in the color blue for this step)
After that, i divided the given mass by the mass of one mol of the compound.
The answer is 0.9307 moles!! I hope this helped you! :))
I did this by finding the atomic mass of each element on the periodic table (my work is in the color blue for this step)
After that, i divided the given mass by the mass of one mol of the compound.
The answer is 0.9307 moles!! I hope this helped you! :))
You might be interested in
Answer:
Partial pressure of nitrogen gas is 0.98 bar.
Explanation:
According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.
where,
= total pressure = 3.9 bar
= partial pressure of nitrogen gas
= partial pressure of oxygen gas
= partial pressure of argon gases
= Mole fraction of nitrogen gas = 0.25
= Mole fraction of oxygen gas = 0.65
= Mole fraction of argon gases = 0.10
Partial pressure of nitrogen gas :
Partial pressure of oxygen gas :
Partial pressure of argon gas :