Set up two equations:
Greg = 330 + 75X
Heather = 660 + 45x
Set them to equal and solve for x:
330 + 75x = 660 + 45x
Subtract 330 from both sides:
75x = 330 + 45x
Subtract 45x from both sides:
30x = 330
Divide both sides by 30:
x = 330 / 30
X = 11
11 months they will have the same amount saved.
Answer:
1. A = 59
2. A = 43
Step-by-step explanation:
If we have a right triangle we can use sin, cos and tan.
sin = opp/ hypotenuse
cos= adjacent/ hypotenuse
tan = opposite/ adjacent
For the first problem, we know the opposite and adjacent sides to angle A
tan A = opposite/ adjacent
tan A = 8.8 / 5.2
Take the inverse of each side
tan ^-1 tan A = tan ^-1 (8.8/5.2)
A = 59.42077313
To the nearest degree
A = 59 degrees
For the second problem, we know the adjacent side and the hypotenuse to angle A
cos A = adjacent/hypotenuse
cos A = 15.3/21
Take the inverse of each side
cos ^-1 cos A = cos ^-1 (15.3/21)
A = 43.23323481
To the nearest degree
A = 43 degrees
-2x^4 + 24x^2 - 10
u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2
a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4
how many constants can a polynomial have ? I am not sure about this one...I wanna say 1 because u can simplify it if it has more then 1...but I am not 100% sure on this one
3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5
when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms
Answer:
m=3
Step-by-step explanation:
expand and move the terms around
18m+4-1=27+10m
8m=24
m=3
Step-by-step explanation:
From the given question it appears that (n-1) is in the numerator's place, if it is so, then let us solve it.
