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maks197457 [2]
3 years ago
11

In which situation is the object experiencing unbalanced forces? A) A box resting on a horizontal floor. B) A car slowing as it

reaches a traffic light. C) A car with its cruise control set to 30 km/h. D) A penny at terminal velocity after falling off of a building.
Physics
2 answers:
Andreyy893 years ago
7 0

Answer:

B) A car slowing as it reaches a traffic light.

Explanation:

Newton's second law states that an object which experiences unbalanced forces has an acceleration, according to the equation:

F=ma

where

F is the net force acting on the object

m is its mass

a is its acceleration

When the forces are unbalanced, it means that the net force F is different from zero, so the acceleration of the object (a) is also different from zero.

Now let's analyze each situation:

A) A box resting on a horizontal floor. --> The object is at rest, so it is not accelerating. This means that the forces acting on it are balanced (net force = 0), so this is not the correct choice

B) A car slowing as it reaches a traffic light. --> The car is slowing down, this means that it has an acceleration: therefore, it is experiencing unbalanced forces. So, this is the correct choice.

C) A car with its cruise control set to 30 km/h. --> The car is moving at constant velocity, so it has zero acceleration. This means that the forces acting on it are balanced (net force = 0), so this is not the correct choice

D) A penny at terminal velocity after falling off of a building. --> The penny is at terminal velocity, which means that it is moving at constant velocity, so it has zero acceleration. This means that the forces acting on it are balanced (net force = 0), so this is not the correct choice.

Therefore, the correct choice is

B) A car slowing as it reaches a traffic light.

evablogger [386]3 years ago
3 0

"Unbalanced forces" show themselves as a change in the speed
or direction of an object's motion.

The only choice where the speed or direction of motion is changing
is the car that's slowing down for the light.

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Explanation:

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The lons entering the mass spectrometer have the same charges. After being accelerated through a potential difference of 8.20 kV
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The calculated magnitude is  6.73 x 10³ V/m.

AMU is described as being one-twelfth the mass of a carbon-12 atom (12C). C makes up more than 98% of the carbon that can be found in nature, making it the most prevalent isotope. The magnitude of the field is the change in potential across a small distance in the indicated direction divided by that distance.

Potential difference = 8.20 kV= 8.20 x 10³ V

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                                                                               = 1.218 m

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A 8.34 × 103-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is
Mnenie [13.5K]

Answer:

21870.3156 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 1.6 m/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-18.2^2}{2\times 162}\\\Rightarrow a=-1.02234\ m/s^2

The acceleration of the craft should be 1.02234 m/s²

F=ma\\\Rightarrow F=8.34\times 10^3\times 1.02234\\\Rightarrow F=8526.3156\ N

Weight of the craft

W=mg\\\Rightarrow W=8.34\times 10^3\times 1.6\\\Rightarrow W=13344\ N

Thrust

F_t=F+W\\\Rightarrow F_t=8526.3156+13344\\\Rightarrow F_t=21870.3156\ N

The thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface is 21870.3156 N

3 0
3 years ago
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Power is the rate of energy. Mathematically, it is

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