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3 years ago

Give two examples where we feel the presence of motion through indirect evidences

1 answer:

8 0

there are situations where the motion is inferred through indirect evidences. For example, we infer the motion of air by observing the movement of dust and the movement of leaves and branches of trees. What causes the phenomena of sunrise, sunset and changing of seasons? Is it due to the motion of the earth? If it is true, why don’t we directly perceive the motion of the earth?

<span>An object may appear to be moving for one person and stationary for some other. For the passengers in a moving bus, the roadside trees appear to be moving backwards. A person standing on the road–side perceives the bus along with the passengers as moving. However, a passenger inside the bus sees his fellow passengers to be at rest</span>

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Pllzzzz help I will mark u as a brainliest

Law Incorporation [45]

Answer:

You dont need BRAINLY there is an app called slader where you scan the textbook barcode and it shows you the answers for the question in the textbook.

Explanation:

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3 years ago

paperclips are more dense than water. however, it's possible to make them float. what property of water allows this? how does th

gayaneshka [121]

Is it surface tension?

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3 years ago

In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t

Mamont248 [21]

Answer:

a) $h_{max}=14536.16 m$

b) $h = 15687.9 m$

c) $PD=7.62\%$ The estimate is low.

Explanation:

a) Using the energy conservation we have:

$E_{initial}=E_{final}$

we have kinetic energy intially and gravitational potential energy at the maximum height.

$\frac{1}{2}mv^{2}=mgh_{max}$

$h_{max}=\frac{v^{2}}{2g}$

$h_{max}=\frac{43^{2}}{2*0.0636}$

$h_{max}=14536.16 m$

b) We can use the equation of the gravitational force

$F=G\frac{mM}{R^{2}}$ (1)

We have that:

$F = ma$ (2)

at the surface G will be:

$G=\frac{gR^{2}}{M}$

Now the equation of an object at a distance x from the surface.

is:

$F=\frac{mgR^{2}}{(R+x)^{2}}$

$m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}$

Using that dv/dt is vdx/dt and integrating in both sides we have:

$v_{0}=\sqrt{\frac{2gRh}{R+h}}$

$h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}$

$h=15687.9$

c) The difference is:

So the percent difference will be:

$PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%$

$PD=7.62\%$

The estimate is low.

I hope it helps you!

7 0

3 years ago

A black Labrador retriever dog leaped into the air to catch a Frisbee an astounding height of 4 ft 9 in. Convert this distance i

Goshia [24]

Answer:

1.448 meters

Explanation:

i looked it up your welcome lol

4 0

3 years ago

d) To calculate air pressure, the volume occupied by air is assumed constant. Why is this incorrect? Explain how the vapor press

Aleks [24]

Answer:

the volume occupied by air is not constant because as we add ethanol in it it will keep decreasing.

vapor pressure calculated and clausius-Claperon plot are affected because volume and vapor pressure are directly proportional.

Explanation:

by charle's law volume and temperature are directly proportional and vapor pressure is directly proportional to temperature thus volume and vapor pressure are also directly proportional by this relation

3 0

3 years ago