Answer:
a) The distance between the ineas doubles, intensity decreases with distance
b) The distance between the ineas doubles
Explanation:
The diffraction pattern of a grid is given as a percentage
d sin θ = m λ
where d give the distance between two consecutive lines, θ it is at an angle, λ the wavelength and m is an integer that determines the order of diffraction, let's not forget that the entire spectrum is at a value of m and then it is repeated.
Let's apply this to our case
a) distance from grid to observation screen doubles
Here we have two effect:
* the energy of the source is constant, it must be distributed over a surface, therefore the intensity decreases with distance
* The other factor can be found using trigonometry
tan θ= y / L
where y is the distance from the central maximum to the line under study and L is the distance to the screen
In general, diffraction experiments cover very small angles
tan θ = sin θ/ cos θ = sin θ
we substitute
sinθ = y / L
we subtitle into the diffraction equation
d y / L = m λ
y = L / d m λ
L = 2 L₀
y = 2 L₀ m λ / d
we see that by doubling the distance to the screen the lines we are seeing are separated by double
b) When the density of lines doubles, it means that in the same distance I have twice as many lines, therefore the distance between two consecutive lines is reduced by half
d = d₀o / 2
y = (L m λ) / d
y = (L m λ/ d₀) 2
we see that The distance between the ineas doubles
