Answer:
0.000136kg/m3
Explanation:
13.6 / 1000 = 0.0136kg/cm3
0.0136 / 100 = 0.000136kg/m3
Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
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Answer:
The answer is 6.40 meters.
Explanation:
The speed v = √(2gh)
v = √( 2×9.8×6.4) = 11.2 m/s
After, finding the time it takes to hit the ground from a height of 1.6 meters.
time = √(2H÷g)
time = √(2×1.6÷9.8)
time = 0.5714 seconds.
Horizontal distance is speed × time = 11.2 × 0.5714 = 6.40 meters.
Energy of gamma rays is given by equation
here we know that
h = Planck's constant
now energy is given as
now by above equation
now for wavelength we can say
