17% of the total number of students are in 1st grade
→0.17×500=85 students in 1st grade
19% of the total number of students are in 4th grade
→0.19×500=95 students in 4th grade
<span>The number of 3rd-grade students is 9 less than the number of 4th-grade students.
→95-9=86 students in 3rd grade
</span><span>The number of 2nd-grade students is 10 less than the number of 5th-grade students.
1st grade+4th grade+3rd grade=85+95+86=266
500-266=234=total number of students in 2nd grade and 5th grade
Let x=2nd grade students
Let y=5th grade students
x+y=234
2nd grade students is 10 less than the number of 5th grade students
→x=y-10
Since x=y-10 so we substitute y-10 for x
→y-10+y=234
→2y-10=234
+10 +10
→2y=244
→2y/2=244/2
→y=122 students in 5th grade
x+y=234
→x+122=234
→x=112 students in 2nd grade
ANSWERS:
1st: 85
2nd: 112
3rd: 86
4th: 95
5th: 122
</span>
Answer:
11^5 and 11 * 11 * 11 * 11 * 11
Step-by-step explanation:
They are the same thing. Both are multiplying eleven 5 times.
Answer:
x=-1 and x=1
Step-by-step explanation:
all you have to do is replace the letters with numbers and
Answer:
3*4. and 0.3*42.00 and 0.03*42
Step-by-step explanation:
Answer:
The amount of oil was decreasing at 69300 barrels, yearly
Step-by-step explanation:
Given
Required
At what rate did oil decrease when 600000 barrels remain
To do this, we make use of the following notations
t = Time
A = Amount left in the well
So:
Where k represents the constant of proportionality
Multiply both sides by dt/A
Integrate both sides
Make A, the subject
i.e. At initial
So, we have:
Substitute in
To solve for k;
i.e.
So:
Divide both sides by 1000000
Take natural logarithm (ln) of both sides
Solve for k
Recall that:
Where
= Rate
So, when
The rate is:
<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>
