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3 years ago

_________ is a preparation of raw seafood marinated in an acidic mixture.

1 answer:

3 0

Mmm this sounds like ceviche to me! It's a Latin American dish with seafood marinated in lemon/lime, cilantro, peppers, and other good stuff!

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Which one is location 3 in___ Arm Center

baherus [9]

Arm. The center is the yellow, in the very middle. I hope this helps.

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3 years ago

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Sevin, the commercial name for an insecticide used to protect crops such as cotton, vegetables, and fruit, is made from carbamic

xeze [42]

Answer:

Explanation:

Ratio of mass of C , N , H and O

= .8007 :0.9333:0.2016:2.133

Ratio of moles of C , N , H and O

= .8007/12 : .9333 / 14 : 0.2016 / 1 : 2.133/16

= .0667 : .0667: .2016 : .1333

= .0667 / .0667 : .0667 / .0667 : .2016 /.0667 : .1333 / .0667

= 1 : 1 : 3: 2

Hence empirical formula = CNH₃O₂

7 .

Weight of titanium Ti = 1.916 g

Weight of oxygen = 3.196 - 1.916 = 1.28 g

Ratio of weight of Ti and O

= 1.916 : 1.28

Ratio of moles of Ti and O

1.916/48 : 1.28/16 [ Molecular weight of Titanium is 48 ]

= .04 : .08

= .04/.04 : .08/.04

= 1 :2 .

Empirical formula

TiO₂

5 0

3 years ago

When a student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, the temperature of the resultant so

zmey [24]

Answer: 54.4 kJ/mol

Explanation:

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=1.0M\times 0.05=0.05mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.0\times 0.05L=0.05mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.05 mole of HCl neutralizes by 0.05 mole of NaOH

Thus, the number of neutralized moles = 0.05 mole

Now we have to calculate the mass of water:

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $50ml+50ml=100ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 100ml=100g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 100 g

$T_{final}$ = final temperature of water = $27.5^0C$

$T_{initial}$ = initial temperature of metal = $21.0^0C$

Now put all the given values in the above formula, we get:

$q=100g\times 4.18J/g^oC\times (27.5-21.0)^0C$

$q=2719.6J=2.72kJ$

Thus, the heat released during the neutralization = 2.72 KJ

Now we have to calculate the enthalpy of neutralization per mole of $HCl$ :

0.05 moles of $HCl$ releases heat = 2.72 KJ

1 mole of $HCl$ releases heat = $\frac{2.72}{0.05}\times 1=54.4KJ$

Thus the enthalpy change for the reaction in kJ per mol of HCl is 54.4 kJ

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3 years ago

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What is Double Decomposition Reaction? _ _ _ koi Zinda bacha hai?

Sholpan [36]

Answer:

It’s when two different elements in a compound get switched

Explanation:

4 0

2 years ago

___________ reactions form predominately or exclusively one enantiomer. ____________ is the addition of a single oxygen atom to

ArbitrLikvidat [17]

1) Stereo-selective (or enantioselective) reactions form predominately or exclusively one enantiomer.

2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.

3) Hydrogenation (or reduction) of an alkene forms an alkane by addition of H₂.

4) Dihydroxylation is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.

5) oxidative cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.

6) Regioselective reactions form predominately or exclusively one constitutional isomer.

7) Syn dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.

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3 years ago