Answer:
Melting points are often used to characterize organic and inorganic crystalline compounds and to ascertain their purity.
Explanation:
1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.
Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume.
It is calculated in mg/ml.
The unit of measurement frequently used for electrolytes is the milliequivalent (mEq). This value compares an element's chemical activity, or combining power, to that of 1 mg of hydrogen.
Formula for calculating concentration in mg/ml is
Conc. (mg/ml) = M(eq) /ml × Molecular weight / Valency
Given
M(eq) NaCl/ ml = 23.5
Molecular weight pf NaCl = 58.5 g/mol
Valency = 1
Putting the values into the formula
Conc. (mg/ml) = 23.5 ×58.5/1
= 1374.75 mg/ml
Hence, 1374.75 is the concentration in milligrams per ml of a solution containing 23.5 meq sodium chloride per milliliter.
Learn more about Concentration here brainly.com/question/14500335
#SPJ4
Both diamond and graphite are allotropes of carbon. Diamond has a high tensile strength but graphite does not.
<h3>What is a molecular model?</h3>
A molecular model is used to describe the actual behavior of a chemical compound based on the kind of bonds that exists in the molecule. Now we are talking about diamond and graphite.
Graphite is composed of hexagonal rings of carbon atoms that form layers that are held together by weak Van Der Walls forces hence they can slide over each other. This is the reason why graphite does not have a high tensile strength.
On the other hand, diamond is made up of octagonal rings of carbon atoms which are rigid and form a strong covalent network solid that explains why graphite has a high tensile strength.
Learn more about diamond and graphite:brainly.com/question/8853712
#SPJ1
I think it got deleted but the answer is Ammonium acetate maybe this is why it got deleted 10-9=1
Here is a site my buddie has to help you. Well co-owner..
https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test