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IRINA_888 [86]
3 years ago
5

* giving stars and thanks *

Chemistry
2 answers:
Montano1993 [528]3 years ago
6 0
This is from top to bottom btw......
a
c
b
b
c
e-lub [12.9K]3 years ago
4 0
The ansewers to the following questions numbers 11-15 are
11. By releasing nitrogen into the air
12. The human population has grown exponentially
13. Pollution
14. Water Pollution
15. Ultraviolet Radiation
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What is the chemical formula of the following compound
OLga [1]
A. C3H10 is the answer
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A block of wood has a density of 0.6g/cm cubed and a volume of 1.2g/cm cubed. What is the mass of the block of wood?
Rus_ich [418]
<span>0.6 = mass/1.2 </span>
<span>mass = 0.6 x 1.2 </span>
<span>= 0.72 g </span>

3 0
3 years ago
Why does increasing the temperature of a reaction cause the reaction rate to increase?
Tems11 [23]
The temperature of a reaction causes its rate of reaction to increase because the heat inputted into the solution excites the electrons that make up the solution, therefore making them move faster, colliding more often with other molecules of the solution. This increase in collision rates causes the rate of reaction to increase.
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3 years ago
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How to find the number of protons in an element?​
Arada [10]

Answer:

Locate the element’s atomic number. The atomic number is located above the element symbol, in the upper left-hand corner of the square. The atomic number will tell you how many protons make up a single atom of an element.

Explanation:

5 0
3 years ago
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Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The
allsm [11]

<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 8.04 days

Putting values in above equation, we get:

k=\frac{0.693}{8.04days}=0.0862days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.0862days^{-1}

t = time taken for decay process = 39 days

[A_o] = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}

[A]=0.278g

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

3 0
3 years ago
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