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ella [17]
2 years ago
11

There is a new treatment to help smokers stop smoking in an experiment, 80% of 300 smokers quit after 10 days of treatment which

of the following is the 95% confidence interval?
(0.7547, 0.8453)
(8096, 08904)
(08048 08952)
(0.749,0 851)
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

(0.755, 0.845)

Step-by-step explanation:

I got it right, on the test so trust me!

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HELP ME
Alex777 [14]

Answer:

<em>Trapezoid ABCD ​ was reflected across the y-axis and then translated 7 units up.</em>

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6 0
3 years ago
How do you put 943,261,586 with base ten numbers
Citrus2011 [14]

Answer:

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586  =  

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

8 0
2 years ago
A boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h.
docker41 [41]

Answer:

A)63miles per hour.

B)27 miles per hour

Step-by-step explanation:

HERE IS THE COMPLETE QUESTION

boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h. What is the boat's speed (in still water)??b) How fast does the current in the river flow?

Let the speed of boat in still water = V(boat)

speed of current=V(current)

To calculate speed of boat downstream, we add speed of boat in still water and speed of current. This can be expressed as

[V(boat) +V(current)]

It was stated that it takes 1hour for the

boat to travels between two points of 90 mi apart downstream.

To calculate speed of boat against current, we will substact speed of current from speed of boat in still water. This can be expressed as

[V(boat) - V(current)]

and it was stated that it takes 2 1/2 for return trip against the Current

But we know but Speed= distance/time

Then if we input the stated values we have

V(boat) + V(current)]= 90/1 ---------eqn(1)

V(boat) - V(current) = 90/2.5----------eqn(2)

Adding the equations we have

V(boat) + V(current) + [V(boat) - V(current)]= 90/2.5 + 90/1

V(boat) + V(current) + V(boat) - V(current)]=90+36

2V(boat)= 126

V(boat)=63miles per hour.

Hence, Therefore, the speed of boat in still water is 63 miles per hour.

?b) How fast does the current in the river flow?

the speed of the current in the river, we can be calculated if we input V(boat)=63miles per hour. Into eqn(1)

V(boat) + V(current)]= 90/1

63+V(current)=90

V(current)= 27 miles per hour

Hence,Therefore, the speed of current is 27 miles per hour.

7 0
3 years ago
What is the slope of the linear function <br> y= -1/3x+1 <br> is it <br> -1/3<br> 1/3<br> -1<br> 1
Zanzabum

Answer:

-1/3

Step-by-step explanation:

This equation is in y-intersept form; y=mx+b, where m is the slope

5 0
2 years ago
The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
3 years ago
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