Answer:
<QOS =150°(opp. <'s of a cyclic quard)
<QRS=75°(< at centre =2×< at circumference)
I don't know about the third one bro
Maybe there's an erroron that quation
Answer: 11
<u>Step-by-step explanation:</u>
3x² - 4x¹¹ + 4x⁴ - 2x¹⁰ - 5 + 8x⁸
To find the degree, look for the largest exponent. <em>11</em>
If you put this polynomial in standard form (from largest to smallest exponent), the first term will give you the degree of the polynomial and the leading coefficient.
- 4x¹¹ - 2x¹⁰ + 8x⁸ + 4x⁴ + 3x² - 5
V=(1/3)hpir^2
aprox
d=2r
d/2=r
d=24
r=24/2=12
V=2713
2713=(1/3)hpi(12^2)
2713=(1/3)hpi(144)
2713=48pih
divide both sides by 48
56.5208=hpi
aprox pi=3.14
divide both sides by 3.14
56.5208/3.14=h=18.0003
height=18cm
Answer:
Step-by-step explanation:
Domain: the set of all permissible input values. In this particular case, x cannot be -3, because that would cause division by zero. Thus, the domain is (-∞, -3) ∪ (-3,∞)
Range: the range consists of the set of all values of y that are possible. Looking at the parent function, y = 1/x, we see that the range of that function is (-∞, 0) ∪ (0,∞); in other words, y gets close to but never actually reaches zero. This is also true of y = -1 / (x + 3).
Thus, the desired range is (-∞, 0) ∪ (0,∞).