All categories

3 years ago

Based on its location on the periodic table, how many electrons does oxygen have in its outer energy level?

Chemistry

2 answers:

amm18123 years ago

5 0

It’s 6 because each oxygen atom has 6 valence electrons

Simora [160]3 years ago

4 0

Answer:

The number of electrons in the outer energy level of oxygen is 6.

Explanation:

Oxygen is present in the group 16 of the periodic table. The electronic configuration of group 16 element is $ns^{2}np^{4}$ . The number of electrons in outer energy level of group 16 element is always found to be 6.

The addition of the number of the electrons present in the valence shell orbitals of oxygen will give the total number of electrons present in the outer energy level.

The number of electron in the outer energy level of oxygen is (2 + 4) = 6.

You might be interested in

Which of these is an example of how engineers have affected society?

Levart [38]

You can eliminate A, C, and D almost instantly if you know that engineers are construction workers. The answer is B.

8 0

3 years ago

Read 2 more answers

My science teacher trying to be cool

Helga [31]

Answer:

omg lol XD

Explanation:

3 0

2 years ago

Consider the following Reaction.

jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol

number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 => 0.5246 moles

Molar mass of H3PO4 = 97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:

3 Mg(OH)2 + 2 H3PO4 ---> Mg3(PO4)2 + 6 H2O

3 mol of Mg(OH)2 reacts with 2 mol of H3PO4 ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2

= (1/3)*0.5246

= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass

= 0.1749 * 262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%

Hope that helps!

3 0

3 years ago

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Cerrena [4.2K]

Answer: The concentration of $H^{+}$ ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

$pH = - log [H^{+}]$

Substitute the value into above expression as follows.

$pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M$

Thus, we can conclude that the concentration of $H^{+}$ ions in vinegar is 0.001 M.

5 0

3 years ago

Substances that are considered acidic are also called alkaline, true or false

V125BC [204]

False
Alkaline is something we use everyday
Acid is something sour eg lemons

7 0

3 years ago

Read 2 more answers