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Anastaziya [24]
3 years ago
14

Based on its location on the periodic table, how many electrons does oxygen have in its outer energy level?

Chemistry
2 answers:
amm18123 years ago
5 0
It’s 6 because each oxygen atom has 6 valence electrons
Simora [160]3 years ago
4 0

Answer:

The number of electrons in the outer energy level of oxygen is 6.

Explanation:

Oxygen is present in the group 16 of the periodic table. The electronic configuration of group 16 element is ns^{2}np^{4}. The number of electrons in outer energy level of group 16 element is always found to be 6.

The addition of the number of the electrons present in the valence shell orbitals of oxygen will give the total number of electrons present in the outer energy level.

The number of electron in the outer energy level of oxygen is (2 + 4) = 6.

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Why is it Xe????????????????
Tamiku [17]

Answer:

Here's what I get.

Explanation:

Ba is element 56. Its electron configuration is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

That's a lot of writing.

To lessen the work, chemists have developed the noble gas notation.

The core electrons of Ba (listed in boldface) have the same electron configuration as Xe, the noble gas found two atoms earlier in the Periodic Table.

Chemists replace the core electron configuration with the symbol of the corresponding noble gas.

The noble gas notation for Ba becomes

Ba: [Xe]6s².

5 0
3 years ago
Whats the answerrrr giving brainliest
viva [34]
B.
I hope this will help a bit (Forgive me of its wrong pls)
7 0
3 years ago
Read 2 more answers
Suppose a salt and a glucose solution are separated by a membrane that is permeable to water but not to the solutes. the nacl so
stira [4]
1)

<span>m(NaCl) = 1.95 g
V(H2O) = 250mL
M(NaCl) = </span><span>58.5 g/mole

Since waters density value is 1g/mL, it can be assumed that volume and mass of water are same values:

</span>V(H2O) = 250ml = 250g = 0.25 kg<span>

</span><span>molality of NaCl:
</span><span>
n(NaCl)=m/M=1.95/58.5= 0.033 mole

</span>molality b(NaCl)=n(NaCl) / V (H2O)= 0.033/0.25 = 0.132 mol/kg
<span>
milimolality of NaOH = 0.132/0,001 = 132 mmole/kg
</span>
milliosmolality of NaOH = milimolality x N of ions formed in dissociation

Since NaCl dissociates into 2 ions in solution:
<span>                                        
</span>milliosmolality of NaOH = 132 x 2 = 264  osmol<span>es/kg
</span>
2)

m(gl) = 9 g
V(H2O) = 250mL
M(NaCl) = 180 g/mole

Since waters density value is 1g/mL, it can be assumed that volume and mass of water are same values:

V(H2O) = 250ml = 250g = 0.25 kg

molality of glucose:

n(gl)=m/M=9/180= 0.05 mole

molality b(gl)=n(gl) / V (H2O)= 0.05/0.25 = 0.2 mol/kg

milimolality of glucose = 0.132/0,001 = 200 mmole/kg

milliosmolality of glucose = milimolality x N of ions formed in dissociation

Since glucose does not dissociate, milimolality and milliosmolality are same:
                                        
milliosmolality of glucose = 200 osmoles/kg

3)

The osmosis represents the diffusion of solvent molecules through a semi-permeable membrane that allows passage solvent molecules but does not to the dissolved substance molecule. The osmosis occurs when the concentrations of the solution on both sides of the membrane are different. Since the semi-permeable membrane only permeates the solvent molecules, but not the particles of the dissolved substance, it occurs the solvent diffusion through the membrane, i.e. the solvent molecules pass through the membrane to equalize the concentration on both sides of the membrane. Solvents molecules move from the middle with a lower concentration in the middle with a higher concentration of dissolved substances.

In our case, osmosis will occur because the concentration of NaCl solution and the concentration of glucose solution do not have same values. Osmosis will occur in the direction of glucose solution because it has a lower concentration.

3 0
3 years ago
At 25 °c, what is the hydroxide ion concentration, [oh–], in an aqueous solution with a hydrogen ion concentration of [h ] = 3.0
chubhunter [2.5K]

As,

Water has a pkw=14

so it can be represented as,

[H+] [OH-] = 1*10^-14

If [H+] = 3*10^-5M

[OH-] = (1*10^-14) / ( 3*10^-5)

[OH-] = 3.3*10^-9 M

5 0
3 years ago
In a given substance, as the temperature of a substance increases, the volume of that substance
steposvetlana [31]
C. Increases. Increasing temperature=Increasing Volume
3 0
2 years ago
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