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3 years ago

Based on its location on the periodic table, how many electrons does oxygen have in its outer energy level?

Chemistry

2 answers:

amm18123 years ago

5 0

It’s 6 because each oxygen atom has 6 valence electrons

Simora [160]3 years ago

4 0

Answer:

The number of electrons in the outer energy level of oxygen is 6.

Explanation:

Oxygen is present in the group 16 of the periodic table. The electronic configuration of group 16 element is $ns^{2}np^{4}$ . The number of electrons in outer energy level of group 16 element is always found to be 6.

The addition of the number of the electrons present in the valence shell orbitals of oxygen will give the total number of electrons present in the outer energy level.

The number of electron in the outer energy level of oxygen is (2 + 4) = 6.

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3 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

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3 years ago

Which material is the lest likely to be recognized as a mixture by looking at it under a microscope ?

Lisa [10]

Hello,

The answer is option C homogeneous mixture.

Reason:

The answer is option C because you can find homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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