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2 years ago

Define or give an example for each of the following terms.

1 answer:

8 0

a) A combound which contains only Carbon and Hydrogen. There are covalent bonds between atoms. Hydrogen form one single bond and Carbon forms four covalent bonds. Carbon bonds can be single, double or triple bonds.

All hydrocarbons are organic compounds, but organic compound can include atoms of other elements.

b) Alkyne has a covalent triple bond between two carbon atoms. Simplest alkyne is ethyne HCCH.

b) Alkane contains only Carbon and Hydrogen and there are single bonds

between atoms. Simplest alkane is methane CH4.

c) An alkene has one double bond between Carbon atoms. Simplest

alkene is ethene H2C=CH2.

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Calculate the specific volume of Helium using the compressibility factor. 500 kPa, 60 degrees Celsius

IrinaK [193]

Explanation:

Formula for compressibility factor is as follows.

z = $\frac{P \times V_{m}}{R \times T}$

where, z = compressibility factor for helium = 1.0005

P = pressure

$V_{m}$ = molar volume

R = gas constant = 8.31 J/mol.K

T = temperature

So, calculate the molar volume as follows.

$V_{m} = \frac{z \times R \times T}{P}$

= $\frac{1.0005 \times 8.314 \times 10^{-3} m^{3}.kPa/mol K \times (60 + 273)K}{500 kPa}$

= 0.0056 $m^{3}/mol$

As molar mass of helium is 4 g/mol. Hence, calculate specific volume of helium as follows.

$V_{sp} = \frac{V_{m}}{M_{w}}$

= $\frac{0.0056 m^{3}/mol}{4 g/mol}$

= 0.00139 $m^{3}/g$

= 0.00139 $m^{3}/g \times \frac{1 g}{10^{-3}kg}$

= 1.39 $m^{3}/kg$

Thus, we can conclude that the specific volume of Helium in given conditions is 1.39 $m^{3}/kg$ .

7 0

2 years ago

Please help asap and thank you

natulia [17]

Answer:

Metamorphic rock

Explanation:

metamorphic rocks do not get hot enough to melt they just get denser if they did they would become igneous rocks.

7 0

2 years ago

What happens to the hydrogen ion (H+) concentration as an aqueous

padilas [110]

Answer:

Explanation:

It can be determined by measuring the Ph. D is incorrect.

C: is wrong because if you are making something acidic, you are increasing the H+

B: is the correct answer.

A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.

7 0

2 years ago

Read 2 more answers

knowing that the reaction of potassium in water is extremely exothermic, what would be the problem with adding a large piece of

anygoal [31]

Answer:

Explanation:

If the reaction is really exothermic (and it is) then the water would spatter all over the place. It would boil off if the container could hold it. It would also react according to the following reaction.

You are talking about a reaction like

2K + 2HOH = 2KOH + H2

8 0

2 years ago

Lithium diisopropylamide (LDA) is used as a strong base in organic synthesis. LDA is itself prepared by an acid-base reaction be

kakasveta [241]

Explanation:

Lithium diisopropylamide (LDA) is used in many organic synthesis and is a strong base. It is prepared by the acid base reaction of N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) and butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ).

The equation is show below as:

[(CH₃)₂CH]₂NH + Li⁺⁻CH₂CH₂CH₂CH₃ ⇒ [(CH₃)₂CH]₂N⁻Li⁺ + CH₃CH₂CH₂CH₃

N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) is a weaker acid and hence, LDA ( [(CH₃)₂CH]₂N⁻Li⁺ ) is stronger base. (Weaker acid has stronger conjugate base)

Butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ) is a very strong base and hence, butane ( CH₃CH₂CH₂CH₃ ) is a very weak acid. (Strong base has weaker conjugate acid)

5 0

2 years ago