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never [62]
3 years ago
7

Define or give an example for each of the following terms.

Chemistry
1 answer:
irakobra [83]3 years ago
8 0

a) A combound which contains only Carbon and Hydrogen. There are covalent bonds between atoms. Hydrogen form one single bond and Carbon forms four covalent bonds. Carbon bonds can be single, double or triple bonds.

  All hydrocarbons are organic compounds, but organic compound can include atoms of other elements.

b)  Alkyne has a  covalent triple bond between two carbon atoms. Simplest alkyne is ethyne HCCH.  

b) Alkane contains only Carbon and  Hydrogen and there are single bonds

  between atoms. Simplest alkane is methane CH4.

c) An alkene has one double bond between Carbon atoms. Simplest

alkene is ethene  H2C=CH2.

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PLS HELP CHEM
Bess [88]

Answer:

Use the formula PV=nRT to get the temperature

7 0
2 years ago
PLEASE HELP ME WITH THIS ONE QUESTION!!
Ksenya-84 [330]
2 I think not 100% tho
5 0
3 years ago
How is the way a mixture is combined different from how a compound is combined?
artcher [175]

Mixture is composed of molecules of different types. A compound can only be separated through chemical means. While a compound is a pure substance that contains 2 or more elements chemically combined together while a mixture are formed when two substances are added together without chemical bonds being formed.

7 0
3 years ago
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

7 0
3 years ago
Which is one way scientists indicate how precise And accurate their experimental measurements are?
nadezda [96]
<span>. They make sure their experiments can be repeated</span>
8 0
3 years ago
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