A rectangular lawn is 48 feet long and 61 feet wide. A path extends diagonally between 2 of the corners of the lawn, what is the
length of the path to the nearest 10th of a foot?
1 answer:
You might be interested in
Answer:
t = 2
Step-by-step explanation:
Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.
Recall that the formula for the position of the vertex in a general parabolic function of the form: , is given by the expression:
In our case, the variable "x" is in fact "t", the leading coefficient () is -5, and the coefficient for the linear term (
) is 20.
Therefore, the maximum of the path will be when
Answer:
The value of y that would make O P parallel to L N = 36
Step-by-step explanation:
This is a question on similar triangles. Find attached the diagram obtained from the given information.
Given:
The length of O L = 14
the length of O M = 28
the length of M P = y
the length of P N = 18
Length MN = MP + PN = y + 18
Length ML = MO + OL = 28+14 = 42
For OP to be parallel to LN,
MO/ML = MP/PN
MO/ML = 28/42
MP/PN= y/(y+18)
28/42 = y/(y+18)
42y = 28(y+18)
42y = 28y + 18(28)
42y-28y = 504
14y = 504
y = 504/14 = 36
The value of y that would make O P parallel to L N = 36
