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Daniel [21]
4 years ago
10

A rectangular lawn is 48 feet long and 61 feet wide. A path extends diagonally between 2 of the corners of the lawn, what is the

length of the path to the nearest 10th of a foot?

Mathematics
1 answer:
Kruka [31]4 years ago
5 0
This is a question that will require Pythagoras' theorem as you want to find the length of a diagonal of a triangle and are given the measurements of two sides. I have attached a picture of how to solve this problem.
To the nearest 10th of a foot, the answer is 77.6ft

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A cyclist completes a journey of 500 m in 22 seconds, part of the way at 10 m/s and the remainder at 50 m/s. How far does she tr
Shtirlitz [24]

Answer:

150 m at 10 m/s

350 m at 50 m/s

Step-by-step explanation:

x + y = 500

x/10 + y/50 = 22

~~~~~~~~~~~~~~~~~

x + y = 500

5x  + y  = 1100

~~~~~~~~~~~~~~~~

x + y = 500

-5x  - y  = -1100

-4x = -600

x = 150

y = 350

3 0
3 years ago
A football team has a squad of 24 players,
lora16 [44]
Answer: 1/3

Explanation:

1/12 of the squad are suspended:

1/12 x 24 = 24/12 = 2

So 2 player are suspended

24 - 2 = 22 player

And some are injured leaving 14 left to play:

22 - 14 = 8 players injured

So 8/24 is the fraction of injured player.

But 8/24 = 1/3 so we can say 1/3 of the whole squad are injured.
4 0
3 years ago
Read 2 more answers
Logan made a 5 foot high castle out of blocks his brothers Simmons want to build one that’s 7.5 feet high what is the scale fact
noname [10]
The answer to the question is 1.5
4 0
3 years ago
A white label wrapped around a rectangular box with square bases covers 80 percent of the lateral surface area of the box. Find
erastova [34]
80% = 6 in
100%=?


100/x 80/6 (proportional relationship)

then cross multiply

600 = 80x
600/80= 7.5

x=7.5
4 0
3 years ago
Read 2 more answers
A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long
Pie

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

                                                          = 3 \times 20 = 60 inches

Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

                                                 =\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}  square inches.

Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

6 0
3 years ago
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