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Anit [1.1K]
3 years ago
6

Please help me with math pt.1

Mathematics
2 answers:
lesya [120]3 years ago
6 0

Answer:

No. of miles Jake rode today = 6.6×2.4 times

= 15.84 miles

1 gallon of gas = 27.6 miles

7 gallons of gas = 193.2 miles

Myla's car can go 193.2 miles with 7 gallons of gas.

All expressions except 7.33×6.

kvv77 [185]3 years ago
3 0

Answer:

i don't think you're in high school

#1. 15.84 (6.6 * 2.4)

#2 193.2 (27.6 * 7)

#3 B and E

Step-by-step explanation:

6.6 * 2.4

27.6 * 7

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Pls help I will mark
tatiyna

Answer:

C

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3 years ago
What is 50% of 82 ? Please help !!
lukranit [14]
If you mean like half then 31?
8 0
3 years ago
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Which equation can be used to calculate the surface area of the triangular prism net show below?
slava [35]

The equation  that can be used to calculate the surface area of the triangular prism net shown below is mathematically given as

SA = (1/2)(5)(12) + (1/2)(5)(12) + (5)(2) + (12)(2) + (13)(2)  

<h3>Which equation can be used to calculate the surface area of the triangular prism net shown?</h3>

Generally, The region or area that is occupied by the surface of any particular item is referred to as that object's surface area.

In conclusion, the equation surface area of the triangular prism will be one that accommodates all parameters

SA = (1/2)(5)(12) + (1/2)(5)(12) + (5)(2) + (12)(2) + (13)(2)  

SA = (1/2)(5)(12) + (1/2)(5)(12) + (5)(2) + (12)(2) + (13)(2)  

Read more about the surface area

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4 0
2 years ago
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

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\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
How many times 700 great then 70
Mariulka [41]
70 X 10 =700

Therefore, it is 10 times greater than 70.

5 0
3 years ago
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