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mr_godi [17]
3 years ago
11

Find the number of real number solutions for the equation. x^2-6=0

Mathematics
2 answers:
pentagon [3]3 years ago
4 0

Answer:

sorry bro i've nev

Step-by-step explanation:er done that before

FromTheMoon [43]3 years ago
4 0

Answer:

its not 1 so its 0

Step-by-step explanation:

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The possible values of b are 7 and 8

<h3>How to determine the possible values of x?</h3>

The expression is given as:

4x² + bx + 3

Next, we test the options to determine the values of b

<u>Option 1: b = 13</u>

So, we have:

4x² + 13x + 3 ---- this cannot be factorized

<u>Option 2: b = 7</u>

So, we have:

4x² + 7x + 3  

Expand

4x² + 4x + 3x + 3

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Factor out x + 1

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<u>Option 3: b = 8</u>

So, we have:

4x² + 8x + 3

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2x(2x +3) + 1(2x + 3)

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<u>Option 4: b = 1</u>

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4x² + x + 3 ---- this cannot be factorized

Hence, the possible values of b are 7 and 8

Read more about factorized expressions at:

brainly.com/question/723406

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