Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 8
Putting x=1.5 in Eqn 1
Dividing both sides by 8
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
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[ - 6 * x^2 * y^8 + 12* x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =
[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =
- xy^6 + 2y - 6
Answer: - xy^6 + 2y - 6
Answer:
Constant rate of change for Jaz height will be 0.5 inch per month
Step-by-step explanation:
Jaz present height is 43 inches.
Eighteen months later her height will be 52 inches.
Now we know rate of change will be represented by the formula
Rate of change of height =
=
= 0.5 inch per month
The constant rate of change for Jaz height will be 0.5 inch per month.
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Answer:
22
Step-by-step explanation:
Range-find the largest number and subtract the smallest number from it
96-74
The average between 12.00 and 15.00 seconds
can be defined in a few different ways.
Way #1: (speed)
Average speed =
(1/2) (the speed at 12 seconds + the speed at 15 seconds) .
Way #2: (speed)
Average speed =
(1/3) (the distance covered between 12.00 and 15.00 seconds)
Way #3: (velocity)
Average velocity =
(1/3) (distance between location at 12 sec and location at 15 sec)
in the direction from location at 12 sec to location at 15 sec.
That's the best we can do with the combination of given and
not given information in the question.
