How much work must you do to push a 13 kg block of steel across a steel table at a steady speed of 1.0 m/s for 8.9 s ? the coeff
1 answer:
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Answer:
Explanation:
Given
Initial speed is u=V
Maximum height of Pebble is H
Deriving maximum height of Pebble and considering motion in vertical direction
where v=final velocity
u=initial velocity
a=acceleration
s=Displacement
Final velocity will be zero at maximum height
i.e. maximum height is dependent on square of initial velocity
for twice the height
on comparing