And what finish the question
Answer:
the frequency heard by the observer is equal to 2677 Hz
Explanation:
given,
velocity of the observer = 17 m/s
speed of the sound = 343 m/s
velocity of the source = 0 m/s
frequency emitted from the source = 2550 Hz

velocity of observer is negative as it is approaching the source. f = 2676.38 Hz ≈ 2677 Hz
hence, the frequency heard by the observer is equal to 2677 Hz
Answer:
<em>(a) t = 4.52 sec</em>
<em>(b) X = 1,156.49 m</em>
Explanation:
<u>Horizontal Launching
</u>
If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity
remains the same in time. The distance x is computed as
.
(a)
The vertical component of the velocity
starts from zero and gradually starts to increase due to the acceleration of gravity as follows

This means the vertical height is computed by

Where
is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0


(b)
We now compute the horizontal distance knowing 

Answer:
6.46393559312 m/s²
Explanation:
Time taken to cover 56 m

Distance covered in 0.42 seconds

From equation of linear motion


The minimum acceleration is 6.46393559312 m/s²
<span>the action of moving something from its place or position.</span>